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slava [35]
2 years ago
6

The heights of a group of boys and girls at a local middle school are shown on the dot plots below. 2 dot plots with number line

s going from 40 to 60. A plot is titled Boy's Heights. There are 0 dots above 40, 1 above 41, 3 above 44, 3 above 46, 2 above 48, 3 above 50, 4 above 52, 4 above 54, and 0 above 56, 58, and 60. A plot is titled Girl's Heights. There are 0 dots above 40 and 41, 2 dots above 44, 3 above 46, 1 above 48, 3 above 50, 4 above 52, 3 above 54, 4 above 56, and 0 above 58 and 60. When comparing the shapes of the two sets of data, what conclusion can someone draw? The shortest boy is taller than the shortest girl. The range for the girls is greater than the range for the boys. There is an outlier in the data for the boys, but not for the girls. The girls are generally taller than the boys. on edge...
Mathematics
1 answer:
andrew-mc [135]2 years ago
6 0

Answer:sushi love sushi sushi is life and life is sushi

Step-by-step explanation:

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Clue is a board game in which you must deduce three details surrounding a murder. In the original game of Clue, the guilty perso
Step2247 [10]

Answer:

the probability is 0.1143

Step-by-step explanation:

here are the details from the question you asked

number of people = 6

nuber of weapons = 6

number of rooms = 9

after narrowing it down to

3 people,3 weapons, and 6 rooms

= ⁶C₃ * ⁶C₃ *⁹C₆ / ²¹C₁₂

= 20 * 20 * 84 / 293930

= 33600/293930

= 0.1143

<u>The probability of making a random guess of the person who is guilty, weapon and location from this choices that have been narrowed down and the guess being correct is 0.1143</u>

7 0
2 years ago
Osvoldo has a goal of getting at least 30\%30%30, percent of his grams of carbohydrates each day from whole grains. Today, he at
Alchen [17]
Hi there! Osvoldo did not meet his goal.

(In my answering I suppose you mean 30%, 220 grams of carbohydrates and 55 grams of whole grains, if this is incorrect, please let me know)

Today Osvoldo ate 220 grams of carbohydrates.
10 % of 220 is 22 (divide by 10), and therefore 30 % of 220 is 22 * 3 = 66. 

If at least 66 grams of Osvoldo's total consumption consisted of whole grains, he would have met his goal. However, he only ate 55 grams of whole grains (which is less than 66), and therefore he did not meet his goal.
8 0
2 years ago
Read 2 more answers
Goodlife charges its members $30 per month for a gym membership. They currently have 75 clients.
Sauron [17]
They should charge $40 per membership, and they will make a maximum revenue of $2400
4 0
1 year ago
Within the United States, approximately 11.25% of the population is left-handed. Of the males, 12.6% are left-handed, compared t
GuDViN [60]

Answer:

There is a 45.05% probability that the selected person is a right-handed female.

Step-by-step explanation:

We have these following probabilities

A 50% probability that a person is a male

A 50% probability that a person is a female.

A 12.6% probability that a male is left-handed.

A 9.9% probability that a female is left-handed.

If a person is selected at random, to find the probability that the selected person is a right-handed female, one would compute:

50% are female.

9.9% of the females are left-handed, so 100-9.9 = 90.1% of the females are right handed.

So

P = 0.5*0.901 = 0.4505

There is a 45.05% probability that the selected person is a right-handed female.

3 0
2 years ago
A sample of 1714 cultures from individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiot
Damm [24]

Answer:

a) p represent the real population proportion of people who showed partial or complete resistance to the antibiotic

b) \hat p=\frac{973}{1714}=0.568 represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

c) We are confident (95%) that the true proportion of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic is between 54.5% to 59.1%.  

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

Description in words of the parameter p

p represent the real population proportion of people who showed partial or complete resistance to the antibiotic

\hat p represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

n=1714 is the sample size required

z_{\alpha/2} represent the critical value for the margin of error

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Part b

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

\hat p=\frac{973}{1714}=0.568 represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

Part c

The confidence interval for a proportion is given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.568 - 1.96 \sqrt{\frac{0.568(1-0.568)}{1714}}=0.545

0.568 + 1.96 \sqrt{\frac{0.56(1-0.56)}{1714}}=0.591

And the 95% confidence interval would be given (0.545;0.591).

We are confident that about 54.5% to 59.1% of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic.  

5 0
2 years ago
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