Question

As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.12. If the cans are currently 12 cm tall, 6 cm in diameter, and have a volume of 339.12 cm3, how much more will the new cans hold? Use 3.14 for π and round your answer to the nearest hundredth.

Answer 1

Answer:

The new can can hold upto volume of 476.69 cubic centimeters.

Step-by-step explanation:

Diameter of the can = d = 6 cm

Radius of the can = r = 0.5d = 0.5 × 6 cm = 3 cm

Height of the can = h = 12 cm

Company wants to increase the dimensions of their cans by a multiple of 1.12. So, the new dimension will be:

r'= 3 cm × 1.12 = 3.36 cm

h' = 12 cm × 1.12 =13.44 cm

Volume of the = can = V

Volume of a cylinder = $\pi r^2h$

$V=\pi r'^2h'$

$=3.14\times (3.36 cm)^2\times 13.44 cm=476.6808 cm^3\approx 476.68 cm^3$

The new can can hold upto volume of 476.69 cubic centimeters.