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Nikitich [7]
2 years ago
8

A 12-kg dog jumps up in the air to catch a ball. The dog's center of mass is normally 0.20 m above the ground, and he is 0.50 m

long. The lowest he can get his center of mass is 0.10 m above the ground, and the highest he can get it before he can no longer push against the ground is 0.30m . If the maximum force the dog can exert on the ground in pushing off is 2.1 times the gravitational force Earth exerts on him, how high can he jump?
Physics
1 answer:
ad-work [718]2 years ago
5 0

Explanation:

Given Data:

mass of dog = 12 Kg

dog's center of mass = 0.20m

length of dog = 0.50m

height of dog's jump = ?

Solution:

Work done of gravitational force = Gain in Potential energy

2.1 × mgΔh = mg (h - 0.1)

2.1 × (0.3 - 0.1) = (h - 0.1)

h = 0.52 m

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A child pushes her toy across a level floor at a steady velocity of 0.50 m/s using an applied force of 2.0 N. If the weight of t
choli [55]
Since toy is moving at constant speed that means that force that child is applying on toy is equal to force of friction.

Rate of speed that toy is moving is irelevant.

childs force is:
Fc = 2N
Fc = Ff  (Ff -friction force)

Ff = a*Q

where Q is weight of the toy and a is friction

if we express a we get
a = F/Q = 2/8 = 0.25
8 0
2 years ago
Read 2 more answers
Upon its return voyage from a space mission, the spacecraft has a velocity of 25000 km/h at point A, which is 7130 km from the c
Nadya [2.5K]

Answer:

the velocity at point B is 27120.08 km/hr

Explanation:

check the picture attached for explanation

5 0
2 years ago
What is the energy of the electron in a helium ion with a charge of +1 in an orbit with a value of n=4?
goldenfox [79]

Answer:

The energy of the electron in a helium ion is -5.44\times10^{-19}\ J

Explanation:

Given that,

Charge = +1

Value of n = 4

Suppose k=2.179\times10^{-18}\ J

We need to calculate the energy of the electron in a helium ion

Using formula of energy

E_{n}=-k\dfrac{z^2}{n^2}

Put the value into the formula

E_{n}=-2.179\times10^{-18}\times\dfrac{2^2}{4^2}

E_{n}=-5.44\times10^{-19}\ J

Hence, The energy of the electron in a helium ion is -5.44\times10^{-19}\ J

8 0
2 years ago
A horizontal force of 50 N is required to push a wagon across a sidewalk at a constant speed.
Tanzania [10]

Answer:

a..... zero

b.... applied force of 50N and frictional force of 50 N both in opposite directions

c..... if mass increases friction will increase so applied force must also increase to keep body in uniform motion

d.... nothing I think all parts answered

7 0
2 years ago
Find the change in volume for a metallic dental filling due to the difference between body temperature (37.0°C) and the temperat
mihalych1998 [28]

Answer:

The change in volume for a metallic dental filling due to the temperature difference is <u>0.1143 mm</u>.

Explanation:

Given:

Temperature of the body is, T_1=37\ \°C

Temperature of the ice-cream is, T_2=-6.2\ \°C

Initial volume of the filling is, V=21.0\ mm^3

Coefficient of thermal expansion is, \alpha =42.0\times 10^{-6}\ K^{-1}

We know that the coefficient of volume expansion is related to thermal expansion as:

\gamma=3\alpha=3\times 42.0\times 10^{-6}=126\times 10^{-6}\ K^{-1}

Now, change in volume for a metallic dental filling is given as:

\Delta V=V\gamma(T_1-T_2)\\\Delta V=21\times 126\times 10^{-6}(37-(-6.2))\\\Delta V=2646\times(37+6.2)\times 10^{-6}\\\Delta V=2646\times 43.2\times 10^{-6}\\\Delta V=0.1143\ mm^3

Therefore, the change in volume for a metallic dental filling due to the temperature difference is 0.1143 mm.

5 0
2 years ago
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