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2 years ago

When the Dragons have lost their most recent game,

Mathematics

1 answer:

lara [203]2 years ago

8 0

Answer:

$t(w)=200\cdot 1.1^w$

Step-by-step explanation:

<u>Exponential Function</u>

We are analyzing a situation where the number of tickets t fans buy depends on the number of consecutive games the Dragons have.

For each consecutive win of the Dragons, the number of tickets fans buy increases by a factor of 1.1. We already know the Dragons have lost the recent game and 200 fans bought tickets. Next time they win, the tickets sold will be

$200\cdot 1.1$

and next time will be

$200\cdot 1.1\cdot 1.1=200\cdot 1.1^2$

We can see the exponent depends on the number of wins (w).

Thus, the function that relates both variables is

$\boxed{t(w)=200\cdot 1.1^w}$

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ololo11 [35]

Answer:

C. Probability is 0.90, which is inconsistent with the Empirical Rule.

Step-by-step explanation:

We have been given that on average, the parts from a supplier have a mean of 97.5 inches and a standard deviation of 6.1 inches.

First of all, we will find z-score corresponding to 87.5 and 107.5 respectively as:

$z=\frac{x-\mu}{\sigma}$

$z=\frac{87.5-97.5}{6.1}$

$z=\frac{-10}{6.1}$

$z=-1.6393$

$z\approx-1.64$

$z=\frac{x-\mu}{\sigma}$

$z=\frac{107.5-97.5}{6.1}$

$z=\frac{10}{6.1}$

$z=1.6393$

$z\approx 1.64$

Now, we need to find the probability $P(-1.64$ .

Using property $P(a$ , we will get:

$P(-1.64$

From normal distribution table, we will get:

$P(-1.64$

Since the probability is 0.90, which is inconsistent with the Empirical Rule, therefore, option C is the correct choice.

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2 years ago

Let m,n,p, and q represent nonzero positive integers. find a number in terms of m,n,p, and q that is halfway between m/n and p/q

alukav5142 [94]

This is the same as averaging. You add them and divide by 2.

((m/n) + (p/q))/2 would be a number in between m/n and p/q.

Do note that n and q must be nonzero, but luckily that is a given.

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2 years ago

Read 2 more answers

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2 years ago

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KonstantinChe [14]

Answer:

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2 years ago

A sample with a sample proportion of 0.4 and which of the following sizes will produce the widest 95% confidence interval when e

Fed [463]

Answer:

C. 50

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

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The higher the margin of error, the wider an interval is.

As the sample size increases, the margin of error decreases. If we want a widest possible interval, we should select the smallest possible confidence interval.

So the correct answer is:

C. 50

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2 years ago