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Anuta_ua [19.1K]
2 years ago
9

Select True or False: PbO2 is oxidized in this process. (Batteries in our cars generate electricity by the following chemical re

action.) Pb + PbO2 + 2H2SO4 → 2PbSO4 + 2H2O
Chemistry
1 answer:
Vlada [557]2 years ago
3 0

Answer :  The given statement is false.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

Pb+PbO_2+2H_2SO_4\rightarrow 2PbSO_4+2H_2O

In this reaction, the oxidation state of Pb is (0), oxidation state of Pb in PbO_2 is (+4) and oxidation state of Pb in PbSO_4 is (+2).

The oxidation-reduction half reaction will be :

Oxidation : Pb\rightarrow Pb^{2+}+2e^-

Reduction : Pb^{4+}+2e^-\rightarrow Pb^{2+}

In this reaction, PbO_2 shows reduction that means it is reduced and Pb shows oxidation that means it is oxidized.

Hence, the given statement is false.

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What is the stoichiometric ratio between BaCl2 and NaCl
bixtya [17]
<span>BaCl2+Na2SO4---->BaSO4+2NaCl There is 1.0g of BaCl2 and 1.0g of Na2SO4, which is the limiting reagent? "First convert grams into moles" 1.0g BaCl2 * (1 mol BaCl2 / 208.2g BaCl2) = 4.8 x 10^-3 mol BaCl2 1.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 7.0 x 10^-3 mol Na2SO4 (7.0 x 10^-3 mol Na2SO4 / 4.8 x 10^-3 mol BaCl2 ) = 1.5 mol Na2SO4 / mol BaCl2 "From this ratio compare it to the equation, BaCl2+Na2SO4---->BaSO4+2NaCl" The equation shows that for every mol of BaCl2 requires 1 mol of Na2SO4. But we found that there is 1.5 mol of Na2SO4 per mol of BaCl2. Therefore, BaCl2 is the limiting reagent.</span>
7 0
2 years ago
What mass of H2 gas (in <br> g. would be produced by the complete reaction of the aluminum block?
loris [4]

First lets calculate the moles of aluminum (molar mass is 27 gram/mol):

n = m/M = 14.9 / 27 = 0.551 mole of Al


According to the reaction between sulfuric acid and aluminum:

From 2 moles of aluminum ==> we get 3 moles of Hydrogen gas

so, let's do cross multiplication

0.551 ==> 0.551 * 3/2 = 0.83 mole of H2


So, from this reaction we got 0.83 mole of H2 gas

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m = n * M = 0.83 * 2 = 1.66 gram of H2


3 0
2 years ago
3 Ni2+(aq) + 2 Cr(OH)3(s) + 10 OH− (aq) → 3 Ni(s) + 2 CrO42−(aq) + 8 H2O(l) ΔG∘ = +87 kJ/molGiven the standard reduction potenti
Mrrafil [7]

Answer:

The standard reduction potential E°cell (Cr6+/Cr3+) is -0.13V

Explanation:

<u>Step 1</u>: Data given

3 Ni^2+(aq) + 2 Cr(OH)3(s) + 10 OH− (aq) → 3 Ni(s) + 2 CrO4^2−(aq) + 8 H2O(l) ΔG∘ = +87000 J/mol

Ni2+(aq) + 2 e− → Ni(s)    E∘red = -0.28 V

<u>Step 2:</u> The half reactions:

Cathode:  Ni2+(aq) + 2 e− → Ni(s)    E° = -0.28 V

Anode: CrO4^2-(aq) + 4H2O(l) +3e- → Cr(OH)3(s) + 5OH- (aq)   E°= unknown

<u>Step 3:</u> Calculate E°cell

ΔG° = -n*F*E°cell

⇒ with ΔG° = the gibbs free energy

⇒ n = the number of electrons in the net reaction = 6

⇒ F = the Faraday constant = 96485 C

⇒ E°cell= the standard cell potential

<u>Step 4:</u> Calculate E°(Cr6+/Cr3+

E°cell= ΔG°/(-n*F)

E°cell = 87000 /(-6*96485)

E°cell = -0.150 V

E°cell = E°(Ni2+/Ni) - E°(Cr6+/Cr3+)

E°(Cr6+/Cr3+) = -0.13V

The standard reduction potential E°cell (Cr6+/Cr3+) is -0.13V

7 0
2 years ago
27. Scott travels north 5 miles and then goes west 3 miles before coming straight back south 2 miles. What is his distance? *
belka [17]

Scott traveled 10 miles in his journey.

<u>Explanation</u>:

Scott first travels 5 miles in north direction, then he turns to west and covers 3 miles distance finally he turns to south and travels 2 miles. We need to find the total distance covered by the Scott. To find the distance we should sum up all the distances he covered in three directions 5 miles north + 3 miles west + 2 miles south = 10 miles.

Therefore we can conclude that the total distance traveled by the Scott is 10 miles.  

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The list below includes some of the properties of ammonia. Identify the physical properties in the list. Check all of the boxes
aleksklad [387]

Answer:

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Strong, unpleasant odor

Dissolves easily in water

Explanation:

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