Given:
Pressure,
= 1300 kPa
Temperature,
= 
= 100 kPa
velocity, v = 40 m/s
A = 1
Solution:
For air propertiess at
= 1300 kPa
= 
= 793kJ/K
= 
and also at
= 100 kPa
= 401 KJ/K
= 
a) Mass flow rate is given by:

Now,
= 46.51 kg/s
b) for the power produced by turbine, 
= 18.231 MW
Answer:
%
Explanation:
Determine the initial velocity


= 19.89 m/s
final velocity


=8.84 m/s
total mechanical energy is given as







Shaft power


mechanical efficiency

%
Answer:
//This Program is written in C++
// Comments are used for explanatory purpose
#include <iostream>
using namespace std;
enum mailbox{open, close};
int box[149];
void closeAllBoxes();
void OpenClose();
void printAll();
int main()
{
closeAllBoxes();
OpenClose();
printAll();
return 0;
}
void closeAllBoxes()
{
for (int i = 0; i < 150; i++) //Iterate through from 0 to 149 which literarily means 1 to 150
{
box[i] = close; //Close all boxes
}
}
void OpenClose()
{
for(int i = 2; i < 150; i++) {
for(int j = i; j < 150; j += i) {
if (box[j] == close) //Open box if box is closed
box[j] = open;
else
box[j] = close; // Close box if box is opened
}
}
// At the end of this test, all boxes would be closed
}
void printAll()
{
for (int x = 0; x < 150; x++) //use this to test
{
if (box[x] = 1)
{
cout << "Mailbox #" << x+1 << " is closed" << endl;
// Print all close boxes
}
}
}
Explanation:
Explanation:
Balancing:
Generally balancing are of two types
1.Static balancing:In this only force balancing is done.
2.Dynamic balancing:in this force as well as moment balancing is done.
Balancing become compulsory for over hanging rotor because unbalance force produce lots of vibration and lots of sound due to this rotor or the whole system in which rotor is attached can be damage.
Answer:
See explanations
Explanation:
Consider the following Venn diagram to retrieve the name of course that student Altvater took during semester I-2015.
• In above Venn diagram inner Ellipse represent the subquery part, this subquery part select the Student ID from STUDENT table.
• Second sub query is used to determine the SectionNo of all student whose studentID retrived in the first subquery
• Finally the main query displays the CourseName from COURSE table.