Answer:
1. Assuming with replacement, the probability is 7.91%; or
2. Assuming without replacement, the probability is 8.64%
Step-by-step explanation:
Total number of golf balls = 24
Let Pr denotes probability, P denotes ProFlights, D denotes DistMax.
The probability of selecting 5 balls can be with or without replacement. Since the question is silent on this, the answers to the methods are provided as follows:
1. Assuming with replacement
Pr(4 P and 1 D) = (18/24) × (18/24) × (18/24) × (18/24) × (6/24)
= 0.75 × 0.75 × 0.75 × 0.75 × 0.25
= 0.0791 = 7.91%
2. Assuming without replacement
Here, we assume that 4 ProFlights are selected first before 1 DistMax is selected, and the probability is as follows:
Pr(4 P and 1 D) = (18/24) × (17/23) × (16/22) × (15/21) × (6/20)
= 0.7500 × 0.7391 × 0.7273 × 0.7143 × 0.3000
= 0.0864 = 8.64%
Therefore, the probability that he reaches in his bag and randomly selects 5 golf balls and 4 of them are ProFlights and the other 1 is DistMax is 7.91% assuming with replacement or 8.64% assuming without replacement.
