Question

Two 4.0-Ω resistors are connected in parallel, and this combination is connected in series with 3.0 Ω. What is the effective resistance of this combination?

Answer 1

Answer

given,

R₁= 4 Ω

R₂ = 3 Ω

When two resistors are connected in series

R = R₁ + R₂

R = 4 + 3

R = 7 Ω

When two resistors are connected in series then their effective resistance is equal to 7 Ω .

When two resistors are connected in parallel.

$\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

$\dfrac{1}{R}=\dfrac{1}{3}+\dfrac{1}{4}$

$\dfrac{1}{R}=\dfrac{7}{12}$

$R = 1.714 \Omega$

Hence, the equivanet resistance in parallel is equal to $R = 1.714 \Omega$