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2 years ago

Add.

Mathematics

2 answers:

Leya [2.2K]2 years ago

8 0

The answer is 6.4

It is positive because the 11.4 is larger than the negatvie 5.

I hope this helps!

Anestetic [448]2 years ago

8 0

Answer:

The answer is 6.4

Step-by-step explanation:

Based on the question

11.4+(-5)

Always remember that + × - = -

So to open the bracket

11.4-5=6.4

Therefore the answer is 6.4

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Angles BAE and FAC are straight angles. What angle relationship best describes angles BAC and DAC?

vova2212 [387]

Answer:

They are adjacent angles

Step-by-step explanation:

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2 years ago

Expand the following expression by using the distributive method. 6(3b - 4c)

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2 years ago

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dangina [55]

Answer:

Step-by-step explanation:

i'm pretty sure that you will have to add it.

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5 0

2 years ago

A study was conducted to determine if there was a difference in the driving ability of students from West University and East Un

Sholpan [36]

Answer:

There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, assuming a significance level 0.1

Step-by-step explanation:

Let p1 be the proportion of West University students who involved in a car accident within the past year

Let p2 be the proportion of East University students who involved in a car accident within the past year

Then

$H_{0}:$ p1=p2

$H_{a}:$ p1≠p2

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{\frac{p*(1-p)*(n1+n2)}{n1*n2} } }$ where

p1 is the sample proportion of West University students who involved in a car accident within the past year (0.15)
p2 is the sample proportion of East University students who involved in a car accident within the past year (0.12)

p is the pool proportion of p1 and p2 ( $\frac{15+12}{100+100}=0.135$ )
n1 is the sample size of the students from West University (100)
n2 is the sample size ofthe students from East University (100)

Then we have z= $\frac{0.03}{\sqrt{\frac{0.135*0.865*(100+100)}{100*100} } }$ ≈ 0.6208

Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.

Assuming significance level 0.1, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance

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2 years ago