Answer:
Ligand A and ligand B can cause same cellular responses in a cell when they are attached to different receptors.
Explanation:
If two same ligands are attached to two different receptors, two different responses will occurs. Such type of response is present in acetylcholine, while when two different ligands attached to two different receptors, same response will occur. This type of response is present in glucagon and epinephrine etc. ligands are responsible for controlling the transcription process when it binds or attached to the DNA molecule of the cell.
The population of the ground squirrels will be limited by the population of the hawks. The population of the hawks, thus, will be a limiting factor for the population of the ground squirrels. The Hawks are the birds of prey that feeds on squirrels. With the increased number of hawks in the same area as them will put these squirrels in danger. The population of the tree squirrels, however, will have no affect on the population of the ground squirrels. The genetic variability and breeding season are not limiting factors for their population either.
Hence, the correct answer is 'option B - a population of hawks'.
Answer:
Malignant melanoma cells would have active telomerases that constantly replenish and lengthen telomeres.
Explanation:
Telomerase can be described as enzymes which add the repetitive sequences called telomeres at the end of a chromosome. Telomeres can be described as repetitive sequences at the end of the chromosome which are involved in protecting the chromosome from any damage.
In a normal skin cell, the telomeres will shorten with time. But in a malignant skin cell, the telomerase will add the repetitive sequence again and again. The telomers will not be able to shorten.
Rate Optimum temperature is 37 degrees celsius.
If you look at the tip of the graph (point C) there is more reaction which means it's the perfect temperature for enzyme reaction
Answer:
a. The formula for finding the number of colonies in a given volume is,
CFU/ml, here CFU is the colony forming units or the number of colonies formed in a volume plated in ml × dilution
The dilution factor given in the question is 1 × 10⁻⁴ and the number of colonies given is 186. Therefore, the number of bacteria present in the given 1 ml of the milk is,
CFU/ ml = 186 / 1 × 10⁻⁴ = 186 × 10⁴.
Hence, the concentration of bacteria in the milk is 186 × 10⁴ CFU/ml.
b) The limit of the bacterial concentration in the pasteurized milk is 20000 CFU/ml, however, it can be seen that the sample of the milk possess more concentration of bacteria than the desired value. Therefore, the milk is not safe to drink by Public Health Standards.