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3 years ago

-) In a poll, 9 out of 25 students in Lydia's science class say they will vote for her for class president.

1 answer:

0 0

A) Divide and compare in decimal form -
9/25 = 0.36
4/6=2/7 = 1/4 = 0.25
0.6... > 0.25

B) Fraction to decimal conversion:
4/16 = 2/8 = 1/4 = 0.25

Use long decision or a calculator - 1 divided by four

C) Again, 9/25 = nine divided by twenty-five = 0.36

% Science class)

0.36 = 36%
Move decimal place to right twice and place “%” at the end.

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Patty is building a rope ladder tree house she needs two 4 foot pieces of rope for the sides of the ladder she needs 6 pieces of

steposvetlana [31]

Answer:

15.5 feet

Step-by-step explanation:

Given:

Patty is building a rope ladder tree house she needs two 4 foot pieces of rope for the sides of the ladder.

She needs 6 pieces of rope each 15 inches long for the steps.

Question asked:

How many feet of rope does patty need to make the ladder ?

Solution:

She needs for the sides of the ladder = Two 4 foot pieces of rope

= 2 $\times$ 4 feet = 8 feet

She needs for the steps of the ladder = 6 pieces of 15 inches long rope

= 6 $\times$ 15 inches = 90 inches

Convert 90 inches into feet:-

12 inches = 1 feet

1 inches = $\frac{1}{12} \ feet$

90 inches = $\frac{1}{12} \times90=\frac{90}{12} =7.5\ feet$

Patty needs total rope = 8 feet + 7.5 feet

= 15.5 feet

Thus, Patty needs 15.5 feet of rope to make the ladder.

6 0

2 years ago

Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0=2x2+3x-8?

Basile [38]

Answer:

Step-by-step explanation:

The given quadratic equation is

2x^2+3x-8 = 0

To find the roots of the equation. We will apply the general formula for quadratic equations

x = -b ± √b^2 - 4ac]/2a

from the equation,

a = 2

b = 3

c = -8

It becomes

x = [- 3 ± √3^2 - 4(2 × -8)]/2×2

x = - 3 ± √9 - 4(- 16)]/2×2

x = [- 3 ± √9 + 64]/2×2

x = [- 3 ± √73]/4

x = [- 3 ± 8.544]/4

x = (-3 + 8.544) /4 or x = (-3 - 8.544) / 4

x = 5.544/4 or - 11.544/4

x = 1.386 or x = - 2.886

The positive solution is 1.39 rounded up to the nearest hundredth

8 0

2 years ago

Read 2 more answers

Ray CE is the angle bisector of ACD. Which statement about the figure must be true? mECD = mECB mACE = mACD ACE DCB

Ainat [17]

Answer:

ACE = ECD is the answer

Step-by-step explanation:

5 0

2 years ago

How many solutions exist for the mixed-degree system graphed below?

Likurg_2 [28]

The answer is one solution. Hope this helps

8 0

2 years ago

Read 2 more answers

The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillat

Greeley [361]

Answer:

1) $L \propto T^2$

Using the condition given:

$2.205 m = K (3)^2$

$K = 0.245 \approx \frac{g}{4\pi^2}$

So then if we want to create an equation we need to do this:

$L = K T^2$

With K a constant. For this case the period of a pendulumn is given by this general expression:

$T = 2\pi \sqrt{\frac{L}{g}}$

Where L is the length in m and g the gravity $g = 9.8 \frac{m}{s^2}$ .

2) $T = 2\pi \sqrt{\frac{L}{g}}$

If we square both sides of the equation we got:

$T^2 = 4 \pi^2 \frac{L}{g}$

And solving for L we got:

$L = \frac{g T^2}{4 \pi^2}$

Replacing we got:

$L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m$

3) $T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s$

Step-by-step explanation:

Part 1

For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

$L \propto T^2$

Using the condition given:

$2.205 m = K (3)^2$

$K = 0.245 \approx \frac{g}{4\pi^2}$

So then if we want to create an equation we need to do this:

$L = K T^2$

With K a constant. For this case the period of a pendulumn is given by this general expression:

$T = 2\pi \sqrt{\frac{L}{g}}$

Where L is the length in m and g the gravity $g = 9.8 \frac{m}{s^2}$ .

Part 2

For this case using the function in part a we got:

$T = 2\pi \sqrt{\frac{L}{g}}$

If we square both sides of the equation we got:

$T^2 = 4 \pi^2 \frac{L}{g}$

And solving for L we got:

$L = \frac{g T^2}{4 \pi^2}$

Replacing we got:

$L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m$

Part 3

For this case using the function in part a we got:

$T = 2\pi \sqrt{\frac{L}{g}}$

Replacing we got:

$T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s$

8 0

2 years ago