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2 years ago

9

A bottle rocket experiences a 500 N force to the right and 300 N of air resistance to the left. Will it accelerate to the left,

right, or not accelerate at all?
A box experiences a 20 N force to the left and two different 8 N forces to the right. Will it accelerate to the left, right, or not at all?

A car experiences a 300 N force to the right from the engine and separate 150 N force due to friction and air resistance to the left. Will it accelerate to the left, right, or not at all?

A rope experiences three 400 N forces to the left and three different 410 N forces to the right.

A skateboard is pushed up a hill with a 90 N force to the left and experiences a gravitational force of 100 N to the right

A box experiences a 20 N force to the left and a 19 N frictional force to the right.

2 answers:

VikaD [51]2 years ago

8 0

The bottle rocket,200 N to the right
the box not at all
the car probably 200N

Finger [1]2 years ago

4 0

<h2>Answer 1) Right </h2><h3> Explanation : </h3>

To find that the acceleration will be on right or left, we need to find the net force between them.

Which is Net F = 500 N - 300 N = 200 N

Therefore, the acceleration will be on right side as it has greater difference as compared to left.

<h2>Answer 2) Left </h2><h3> Explanation : </h3>

Here, the right side will have 2 forces of 8 N which gives the total of 16 N.

Using the net force calculation = 20 N - 16 N = 4 N.

Therefore, the box will accelerate towards left-side.

<h2>Answer 3) Right </h2><h3>Explanation : </h3>

In this case, the car is experiencing +300 N to the right and -150 N on left.

On calculating the net force = +300 N- 150 N = +150 N.

Here, right side has 150 N greater force than left side. Therefore, the car will accelerate towards right.

<h2>Answer 4) Right </h2><h3>Explanation : </h3>

The rope will move towards right as the net force will be 10 N towards right.

By calculating the net force = 410 N - 400 N = 10 N.

This clearly indicates that the rope will move towards right.

<h2>Answer 5) Right </h2><h3>Explanation: </h3>

The skateboard will accelerate towards right as the force will be 10 N more on right than on left.

As the net force will be = 100 N - 90 N = 10 N.

Since, the 10 N more force is on right the acceleration will be on right.

<h2>Answer 6) Left </h2><h3>Explanation : </h3>

The box will experience acceleration towards left as there will be greater 1 N force on left as compared to right.

On calculating the net force = 20 N - 19 N = 1 N

This shows that the box will accelerate on left side.

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Answer:

The standard reduction potential E°cell (Cr6+/Cr3+) is -0.13V

Explanation:

<u>Step 1</u>: Data given

3 Ni^2+(aq) + 2 Cr(OH)3(s) + 10 OH− (aq) → 3 Ni(s) + 2 CrO4^2−(aq) + 8 H2O(l) ΔG∘ = +87000 J/mol

Ni2+(aq) + 2 e− → Ni(s) E∘red = -0.28 V

<u>Step 2:</u> The half reactions:

Cathode: Ni2+(aq) + 2 e− → Ni(s) E° = -0.28 V

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<u>Step 3:</u> Calculate E°cell

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E°cell= ΔG°/(-n*F)

E°cell = 87000 /(-6*96485)

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E°(Cr6+/Cr3+) = -0.13V

The standard reduction potential E°cell (Cr6+/Cr3+) is -0.13V

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If you were to perform the reaction KCl (s)→K+ (g)+ Cl−(g), would energy be absorbed or released? Lattice Energies for Some Ioni

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Answer:

Energy would be absorbed.

Explanation:

Lattice energy is defined as the energy required to break apart an ionic solid and convert its component atoms into gaseous ions. That is what you're doing in:

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The energy you require to obtain this reaction is 701 kJ/mol. As the value is positive, <em>energy would be absorbed.</em>

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Answer:

2,4,4-trimethyl-2-pentene yields mixture of $(CH_{3})_{2}C=O$ and $(CH_{3})_{3}CHO$

Explanation:

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Ketone is formed from di-substituted side of double bond and aldehyde is formed from mono-substituted side of double bond.

Ozoznolysis involves two consecutive steps : (1) formation of ozonide, (2) hydrolysis of ozonide.

Hydrolysis can be done with/without using reducing agent. Carboxylic acid/carbon dioxide/ketone is produced when hydrolysis is done without using reducing agent.

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To determine the concentration of ethanol in cognac a 5.00 mL sample of the cognac is diluted to 0.500 L. Analysis of the dilute

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Answer : The molar concentration of ethanol in the undiluted cognac is 8.44 M

Explanation :

Using neutralization law,

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$V_1$ = volume of undiluted cognac = 5.00 mL = 0.005 L

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Now put all the given values in the above law, we get molar concentration of ethanol in the undiluted cognac.

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$M_1=8.44M$

Therefore, the molar concentration of ethanol in the undiluted cognac is 8.44 M

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Answer:

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Explanation:

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