Answer: The answer is 
Step-by-step explanation: Given that Kayleigh babysat for 11 hours the present week. Also, this was 5 less than two-third of the number of hours she babysat last week, which is represented by 'h'.
We are to write an equation to represent the number of hours she babysat each week.
So, for that, let 'x' be the number of hours she babysat this week. Then, according to the question, we can write
Also, it is given that
Therefore,
Hence, using the above relation, we can find the number oh hours Keyleigh babysat each week.
Thus, the required equation is
where, 'x' and 'h' are the number of hours she sat this week and last week respectively.
Answer:
4 shelves
Step-by-step explanation:
if there is 8 shelves that display 1 car then that means there is 8 cars total.
so if you need a total of 12 cars then you would do (total of cars needed - total of cars you have).
(12-8) which would equal 4.
you need 4 cars left but on each shelf going forward needs to have 2 cars on it.
now since you have 4 cars you would divide that by the amount of cars on each shelf going forward.
4/2) which equals 2.
you need 2 more shelfs for the 4 cars needed.
Answer:
test statistic (Z) is 2.5767 and p-value of the test is .009975
Step-by-step explanation:
: percentage of students who smoke did not change
: percentage of students who smoke has changed
z-statistic for the sample proportion can be calculated as follows:
z=
where
- p(s) is the sample proportion of smoking students (
=0.25)
- p is the proportion of smoking students in the survey conducted five years ago (18% or 0.18)
- N is the sample size (200)
Then, z=
≈ 2.5767
What is being surveyed is if the percentage of students who smoke has changed over the last five years, therefore we need to seek two tailed p-value, which is .009975.
This p value is significant at 99% confidence level. Since .009975 <α/2=0.005, there is significant evidence that the percentage of students who smoke has changed over the last five years
For these lines, let
.
And for these, let
.
Now,
The vertices of
in the x-y plane are (0, 2), (2/3, 10/3), (2, 2), and (4/3, 2/3). Applying
to each of these yields, respectively, (2, 2), (2, 4), (-2, 4), and (-2, 2), which are the vertices of a rectangle whose sides are parallel to the u-v plane.
