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tensa zangetsu [6.8K]
2 years ago
12

If 0.25 mol of HClO2 is added to enough water to prepare a 0.25 M HClO2 aqueous solution, what is the concentration of H3O+(aq)

at equilibrium? At this temperature, Kc is 0.15 for the equation, HClO2(aq) + H2O(l) ⇌ H3O+(aq) + ClO2−(aq)
Chemistry
1 answer:
hammer [34]2 years ago
5 0

Answer:

The concentration of H3O+= 0.15M

Explanation:

From The equation of reaction

HClO2(aq) + H2O(l) ⇌ H3O+(aq) + ClO2−(aq)

0.25mol HClO2(aq) 0.25mol producesClO2−(aq) and x-mol of H3O+

Using Kc = [H3O+][ClO2-]/[HClO2]

0.15= 0.25*x/0.25

Simplify

x=0.15M

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In this problem, you will use Lenz's law to explore what happens when an electromagnet is activated a short distance from a wire
Vsevolod [243]

Answer:

The correct answer is Option A (There is no magnetic flux through the wire loop.)

Explanation:

Magnetic flux measures the entire magnetic field that passes through the wire loop.

The right hand rule can be demonstrated on how magnetic flux is generated through the moving current in the wire loop. The magnetic flux through the wire loop  will decrease as it moves upward through the magnetic field region.

If the direction of the vector area of the wire loop is to the right, and the switch is closed, it will push the magnetic flux to the right which will now be increased due to an equal increase in the current in the wire loop. But, when the switch is open, this will halt the movement of current through the wire loop thus affecting the generation of magnetic field. This would make the magnetic flux to be zero.

4 0
2 years ago
What is the molar mass of 56.75 g of gas exerting a pressure of 2.87 atm on the walls of a 5.29 l container at 230 k?
laiz [17]
We first need to find the number of moles of gas in the container 
PV = nRT
where;
P - pressure - 2.87 atm x 101 325 Pa/atm = 290 802.75 Pa
V - volume - 5.29 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 230 K
substituting these values in the equation 
290 802.75 Pa x  5.29 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 230 K
n = 0.804 mol
the molar mass = mass present / number of moles
molar mass of gas = 56.75 g / 0.804 mol 
therefore molar mass is 70.6 g/mol 
8 0
1 year ago
A student needed exactly 45.3ml of a solution. what piece of glassware should that student use? justify your choice.
Darina [25.2K]
The student should use the graduated cylinder. A graduated is the most common laboratory glassware when measuring volumes. It has calibrations by 1, 0.5 or 0.1 depending on the maximum volume. You have to make sure though, that you measure the volume by looking at the lower meniscus of the liquid at eye level.
7 0
1 year ago
when the volume of a gas is changed from 3.75 L to 6.52 L the temperature will change from 100k to _K
harkovskaia [24]

The temperature will change from 100K to 173.87 K

calculation

by use of    law  that is V1/T1=V2/T2

V1=3.75 L

T1=100k

V2=6.53 L

T2=?

make T2 the subject of the formula

T2=(V2 xT1)V1

=6.52 x100/3.75=173.87K


4 0
2 years ago
Read 2 more answers
If 42.1 mL of 1.02 M sodium hydroxide, measured using a graduated cylinder, is placed in a beaker filled with 300 mL of DI water
lys-0071 [83]

Answer:

Approximately 0.126 M

Explanation:

For the calculation of the dilution you take into account the moles of NaOH in the 42.1mL of the original solution and you use the new volume of 342.1 mL:

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The standardization is necessary because a beaker is not not an instrument used to measure volumes and the marks on it only give an estimate of the volume of the solution, they are used to contain solutions and carry reactions among other things. If you would have measured the water with a graduated cylinder (an instrument designed to measure volumes) the standardization wouldnt be that necessary.

5 0
2 years ago
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