Answer:
Family will save 3600 gallons of water by replacing the shower-heads.
Step-by-step explanation:
Number of family members in a family = 5
Each member of the family averages shower per day = 8 minutes
Total time for shower = 5×8 = 40 minutes
With a 5 gallon shower-heads each member will use water in a day = 5×40 = 200 gallons
Water consumption in 30 days = 200×30 = 6000 gallons per month
After replacing the shower-heads with 2 gallons per minute shower-heads family will use the amount of water = 40×2= 80 gallons per day
Water used in one month = 80×30 = 2400 gallons
Now water save by the family in 30-day period = 6000 - 2400 = 3600 gallons
Therefore, family will use 3600 gallons less water by replacing the water saving water heads.
ANSWER:
C. Place the compass on point A. Open the compass to a point between point P and point B.
EXPLANATION:
A perpendicular is a line that would be at a right angle to line BA.
The next step is to chose a radius that is greater than PB or PA so as to construct the bisector. And this can be done by placing the compass on point A, and open the compass to a point between point P and point B.
Use this radius to draw an arc above and below the line, and repeat the same using B as the center with the same radius. This would form two intersecting arcs above and below line BA. Join the point of intersection of the arcs by a straight line through P. This is the bisector of line BA through point P.
We simply need to solve for the circumference of the imaginary circle.
Given:
Diameter = 25 feet.
Circumference = 2 * radius * π OR Circumference = diameter * π
C = 25feet * 3.14
C = 78.50 feet
The pony will walk 78.50 feet to complete one trip around the circle.
Answer:
1) The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Step-by-step explanation:
Given : Assume there are 365 days in a year.
To find : 1) What is the probability that ten students in a class have different birthdays?
2) What is the probability that among ten students in a class, at least two of them share a birthday?
Solution :

Total outcome = 365
1) Probability that ten students in a class have different birthdays is
The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...

The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday
P(2 born on same day) = 1- P( 2 not born on same day)
![\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B365%7D%7B365%7D%5Ctimes%20%5Cfrac%7B364%7D%7B365%7D%5D)
![\text{P(2 born on same day) }=1-[\frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B364%7D%7B365%7D%5D)

The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Answer:
9
Step-by-step explanation:
Multiply the total number of tiles by the fraction of tiles that are blue
24 *3/8
24/8 *3
3*3
9