Question

What is the product of (3 y Superscript negative 4 Baseline) (2 y Superscript negative 4 Baseline)?

Answer 1

Answer: $\frac{6}{y^8}$

Step-by-step explanation:

For this exercise it is necessary to remember a property called the "Product of powers property".

The Product of powers property states the following:

$(a^m)(a^n)=a^{(m+n)}$

Where "a" is the base and "m" and "n" are exponents.

As you can observe, when you have the same base multiplying, you need to rewrite the base and add the exponents.

In this case you have the following expression given in the exercise:

$(3y^{-4})(2y^{-4})$

Then, applying the Product of powers property explained at the beginning of this explanation, you get the following product:

$(3y^{-4})(2y^{-4})=6y^{(-4+(-4))}=6y^{(-4-4)}=6y^{-8}$

Now, according to the Negative exponent Rule:

$a^{-n}=\frac{1}{a^n}$

Therefore, the result is:

$=\frac{6}{y^8}$

Answer 2

Answer:

Option A on Edgnu

Step-by-step explanation:

100% on quiz