Answer:
C. 160 minutes
Step-by-step explanation:
The calculation to be made will be to process 20 students
We have, according to the exercise, the following data:
For process 1: Registration table, Number of servers = 1, Time spent = 2 minutes
For process 2: cashier, number of servers = 3, time spent = 10 minutes
For process 3: ID processing station, number of servers = 4, time spent = 20 minutes
Demand rate = 0.125
To solve it, we will look for the capacity that the server has of the previously mentioned processes, calculating the following:
Capacity = Number of students served per minute
We can say that at the registration table we observe:
Time needed to serve 1 student = 2 minutes
Capacity = 0.5 students per minute
With the cashier we analyze the following:
Time needed to serve 1 student = 10 minutes
Number of servers = 3
Capacity = 0.3 students per minute
ID processing station
Time needed to serve 1 student = 20 minutes
Number of servers = 4
Capacity = 0.2 students per minute
When comparing the processes, it is definitely found that the bottleneck is the ID processing station, where it takes more time to serve a student, which leads us to infer that the capacity of the process is comparable to the capacity of the process bottleneck
Process capacity = 0.2 students per minute
Given, demand rate = 0.125 students per minute
We observe that the demand rate is less than the capacity of the process, therefore we can infer that the number of students served during each minute is the same as the demand rate.
In this way we find that:
Number of students served per minute = 0.125
Time needed to serve 1 student = 1 / 0.125 = 8 minutes
Time needed to serve 20 students = 8 x 20 = 160 minutes.
We conclude that the answer is that it will take 160 minutes to serve 20 students.
.
