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alisha [4.7K]
2 years ago
9

The light reactions of photosynthesis use _____ and produce _____. The light reactions of photosynthesis use _____ and produce _

____. water ... NADPH NADPH ... NADP carbon dioxide ... oxygen NADPH ... oxygen carbon dioxide ... sugar
Chemistry
1 answer:
SashulF [63]2 years ago
8 0
<h2>Input = NADP^+, water and Output = NADPH + O_2</h2>

Explanation:

The light reactions of photosynthesis use water and produce Oxygen, NADPH.

The equation for photosynthesis :

6 CO_2 + 6 H_2O → C_6H_12O_6 + 6 O_2

The process of photosynthesis in two stages -

  • The first stage is called the light reaction in which the light energy from the sun is captured and converted into chemical energy stored in the form of ATP and NADPH
  • The second stage is the process of conversion of ATP molecules to sugar or glucose (the Calvin Cycle)

For a light reaction -

Net Input is of, NADP^+, Light, Water, ADP

Net Output is of, ATP, NADPH, O_2

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A student constructs an electrochemical cell. A diagram of the operating cell and the unbalanced ionic equation representing the
vivado [14]

Answer:

A voltaic cell

Explanation:

A voltaic cell is a device which converts chemical energy to electrical energy. The chemical reactions that take place inside the cell causes electrons to flow from anode to cathode hence, electricity is produced. A simple voltaic cell is made by placing two different metals in contact with an electrolyte separated by a salt bridge. The cathode is the negative electrode while the anode is the positive electrode. It is also called a galvanic cell.

In a voltaic cell having a copper/copper solution half cell, reduction occurs at the cathode. Hence, at the cathode copper II ions accept two electrons and become reduced to ordinary metallic copper. This causes the blue colour of the solution to become discharged (fade) as the cell continues to function.

4 0
2 years ago
Given the following reactions Fe2O3 (s) + 3CO (s) → 2Fe (s) + 3CO2 (g) ΔH = -28.0 kJ 3Fe (s) + 4CO2(s) → 4CO (g) + Fe3O4(s) ΔH =
Taya2010 [7]

Answer: The enthalpy of the reaction is -109 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Fe_2O_3(s)+3CO(s)\rightarrow 2Fe(s)+3CO_2(g)   \Delta H=-28.0kJ  \times 3    

3Fe_2O_3(s)+9CO(s)\rightarrow 6Fe(s)+9CO_2(g)   \Delta H=-84.0kJ     (1)

3Fe(s)+4CO_2(s)\rightarrow 4CO(g)+Fe_3O_4(s) \Delta H=+12.5kJ  \times 2  

6Fe(s)+8CO_2(s)\rightarrow 8CO(g)+2Fe_3O_4(s) \Delta H=+25.0kJ     (2)

The final reaction is:

Subtracting (2) from (1):

3Fe_2O_3(s)+CO(g)\rightarrow CO_2(g)+2Fe_3O_4(s) \Delta H=-84.0-(+25.0)=-109kJ

Thus the enthalpy of the reaction is -109 kJ

7 0
2 years ago
Interpret the following Arterial Blood Gases 1. pH 7.33 PaCO2 60 HCO3 34 A. Normal ABG values B. Respiratory acidosis without co
kicyunya [14]

Answer: 1) C; 2)D; 3)B; 4)B; 5) A

Explanation:Interpreting the following Arterial Blood gases, we have

1. pH 7.33 PaCO2 60 HCO3  34----Respiratory acidosis with partial compensation----C

2. pH 7.48 PaCO2 42 HCO3 30------. Metabolic alkalosis without compensation----D

3. pH 7.38 PaCO2 38 HCO3 24 ----- Normal---B

4. pH 7.21 PaCO2 60 HCO3 24------ Respiratory acidosis without compensation-----B

5. pH 7.48 PaCO2 28 HCO3 20 ----Respiratory alkalosis with partial compensation

The Arterial blood gas interpretation  from analysis shows  the pH and the partial pressures of oxygen and carbon dioxide in the arterial blood of an individual which can detect how well the lungs are functioning thereby making a physician make a diagnosis, estimate  the severity of a condition and profer treatment.

4 0
2 years ago
How many moles of lithium chloride will be formed by the reaction of chlorine with 0.046 mol of lithium bromide in the following
Feliz [49]

Answer:

The answer is 0.046 mol.

Explanation:

By looking at the balanced equation, you can form a ratio of lithium chloride and lithium bromide using the coefficient value :

ratio of lithium bromide <u>(</u>2LiBr)

= 2

ratio of lithium chloride (2LiCl)

= 2

So the ratio is 2 : 2 then simplify into 1 : 1 . Which means that 1 mol of lithium bromide is equal to 1 mole of lithium chloride.

In this case, 0.046 mol of lithium bromide will form <u>0</u><u>.</u><u>0</u><u>4</u><u>6</u><u> </u><u>m</u><u>o</u><u>l</u> of lithium chloride.

8 0
2 years ago
A 50.0 mL Erlenmeyer flask filled with 1-hexanol has a mass of
Iteru [2.4K]
Yes it is correct for that answer
4 0
2 years ago
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