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2 years ago

A 50.0 mL Erlenmeyer flask filled with 1-hexanol has a mass of

Chemistry

2 answers:

mash [69]2 years ago

6 0

Answer: The density of 1-hexanol will be $0.8136g/ml$

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}$

Given :

Mass of Erlenmeyer flask + Mass of 1-hexanol = 61.45 grams

Mass of Erlenmeyer flask = 20.77 g

Mass of 1-hexanol = (61.45 - 20.77) g = 40.68 g

Volume of Erlenmeyer flask= Volume of 1-hexanol = 50 ml

Putting in the values we get:

$Density=\frac{40.68g}{50ml}=0.8136g/ml$

Thus density of the 1-hexanol will be $0.8136g/ml$

Iteru [2.4K]2 years ago

4 0

Yes it is correct for that answer

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A metal crystallizes with a face-centered cubic lattice. The edge of the unit cell is 417 pm. The diameter of the metal atom is:

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Answer:

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2 years ago

A student dissolved 4.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution

mihalych1998 [28]

Answer:

0.08097 grams of nitrate ions are there in the final solution.

Explanation:

Moles of cobalt(II) nitrate ,n= $\frac{4.00 g}{245 g/mol}=0.01633 mol$

Volume of the cobalt(II) nitrate solution, V = 100.0 mL = 0.1 L

$Molarity=\frac{n}{V(L)}$

Let the molarity of the solution be $M_1$

$M_1=\frac{0.01633 mol}{0.1 L}=0.1633 M$

A students then takes 4 .00 mL of $M_1$ solution and dilute it to 275 ml.

$M_1=0.1633 M$

$V_1=4.00 mL$

$M_2=?$ (molarity after dilution)

$V_2=275 mL$ (after dilution)

$M_1V1=M-2V_2$

$M_2=\frac{M_1V_1}{V_2}=\frac{0.1633 M\times 4.00 mL}{275 mL}=0.002375 M$

Molarity of the of solution after dilution is 0.002375 M.

$Co(NO_3)_2(aq)\rightarrow Co^{2+}(aq)+2NO_3^{-}(aq)$

1 mol of cobalt(II) nitrate gives 2 moles of nitrate ions. Then 0.002375 M solution of cobalt (II) nitrate will give:

$[NO_3^{-}]=\frac{2}{1}\times 0.002375 M=0.004750 M$

Moles of nitrate ions = n

Volume of the solution = 275 mL = 0.275 L

Molarity of the nitrate ions = $[NO_3^{-}]=0.004750 M$

$[NO_3^{-}]=\frac{n}{0.275 L}$

n = 0.001306 mol

Mass of 0.001306 moles of nitrate ions:

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0.08097 grams of nitrate ions are there in the final solution.

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2 years ago

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AveGali [126]

Answer:

$M_{i} = M_{i} + C_{xjxk} (1-2x_{i})$ ...1

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Explanation:

The ternary constant is given by the following equation:

The symbol XiXi, where XX is an extensive property of a homogeneous mixture and the subscript ii identifies a constituent species of the mixture, denotes the partial molar quantity of species ii defined by

$M_{i} = [\frac{d(nM)}{dn_{i} }]_{P,t,n,j}$

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