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alukav5142 [94]
2 years ago
14

You are instructed to deliver about 2 mL of water from a buret with a precision of 0.01 mL. Which of the following measured volu

mes is consistent with these instructions. a. 2.03 mL b. 1.87 mL C. 2.0 ml d.1.999 mL
Chemistry
1 answer:
nikitadnepr [17]2 years ago
7 0

Answer:

C. 2.0 mL

Explanation:

This value is due to the fact that the burettes are instruments that allow accurately measure volumes of liquids, in this case it has a precision of ±0.01 mL, which indicates that this is the smallest value that the burette can measure with accuracy, which indicates that 2 mL can be measured accurately without any problem.

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Calculate the pOH of a solution that contains 3.9 x 10-5 M H3O+ at 25°C.
exis [7]

Answer:

Option b. 9.59

Explanation:

First, let us calculate the pH. This is illustrated below:

[H3O+] = 3.9 x 10-5 M

pH = —Log [H3O+]

pH = —Log [3.9 x 10-5]

pH = 4.41

Recall: pH + pOH = 14

4.41 + pOH = 14

Collect like terms

pOH = 14 — 4.41

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2 years ago
Determine the percent yield for the reaction between 6.92 g K and 4.28g of oxygen gas if 7.36 g of potassium oxide is produced.
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Answer:

percentage yield = 88.25%

Explanation:

Firstly, write the chemical reaction and balance the equation.

Potassium react with oxygen to produce potassium oxide.

K + 02 → K2O

Balance the equation

4K + 02 → 2K2O

The limiting reactant is K so the yield of potassium oxide can be calculated using grams for potassium.

atomic mass of K = 39.1g/mol

grams for 4 mole of potassium =  4(39.1) = 156.4 g

grams for 2 moles of K2O = 2( 39.1 × 2 + 16) = 188.4 g

If 156.4 g of K produces 188.4 g of K2O

6.92 g of K will produce ? gram of K2O

cross multiply

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grams of K2O = 1303.72/156.4

grams of K2O = 8.33585677749

grams of K2O = 8.34 g

percentage yield = actual yield/theoretical yield × 100

actual yield = 7.36 g

theoretical yield = 8.34 g

percentage yield = 7.36/8.34 × 100

percentage yield =         736/8.34

percentage yield = 88.2494004796%

percentage yield = 88.25%

5 0
2 years ago
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Heat = mC(T2-T1)
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ΔT = 0.42 °C change in temperature

8 0
2 years ago
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