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2 years ago

What is the average rate of change in f(x) over the interval [4,13]?

Mathematics

2 answers:

Andrew [12]2 years ago

8 0

I took a picture of the answer for you.

Andru [333]2 years ago

6 0

Answer:

1/3 is the average rate of change

Step-by-step explanation:

Change in an interval is = Final - Initial

Since a = 4 (initial) and b = 13 (final)

f(x) = f(4) = 8 (initial)

= f(13) = 11 (final)

Substitute for the formula

$A = \frac{11 - 8}{13 - 4}\\ \\A = \frac{3}{9}$

Simplify further

A = 1/3

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Leslie started last week with $1200 in her checking account. During the week, she wrote the checks below.

kifflom [539]

Answer: B
Look at the line where it says 935 54
Leslie goes to the salon and pays $30
$935.54 - $30 = $905.54

However, the line after the $30 says $900.59, which is incorrect.

Hope this helps!

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2 years ago

Read 2 more answers

If the instructions for a problem ask you to use the smallest possible domain to completely graph two periods of y = 5 + 3 cos 2

erica [24]

Hello,

y=5+3*cos (2(x-π/3))

The function is periodic with periode=2π.

-1<=cos (2(x-π/3))<=1
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2 years ago

6x+7y=4x+4y6x+7y=4x+4y6, x, plus, 7, y, equals, 4, x, plus, 4, y Complete the missing value in the solution to the equation. ((l

tia_tia [17]

Answer:

<h3>The missing value in the solution to the equation is 6.</h3><h3>So, the complete solution is (6, -4).</h3>

Step-by-step explanation:

Given:

6x+7y=4x+4y.

( ,-4)

Now, to complete the missing value in the solution to the equation.

As, the equation is:

$6x+7y=4x+4y$

And, the solution is:

$(x,y)=(\ \ ,-4)$

Now, solving the equation by putting the value of $y=-4$ :

$6x+7(-4)=4x+4(-4)\\\\6x+(-28)=4x+(-16)\\\\6x-28=4x-16\\\\$

Adding both sides by 28 we get:

$6x=4x+12$

Subtracting both sides by $4x$ we get:

$2x=12$

Dividing both sides by 2 we get:

$x=6.$

Thus, the solution to the equation is (6, -4).

Therefore, the missing value in the solution to the equation is 6.

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2 years ago

Davison Electronics manufactures two LCD television monitors, identified as model A andmodel B. Each model has its lowest possib

shtirl [24]

The question is incomplete. The complete question is :

Davison Electronics manufactures two LCD television monitors, identified as model A and model B. Each model has its lowest possible production cost when produced on Davison’s new production line. However, the new production line does not have the capacity to handle the total production of both models. As a result, at least some of the production must be routed to a higher-cost, old production line. The following table shows the minimum production requirements for next month, the production line capacities in units per month, and the production cost per unit for each production line:

Production per unit Minimum production

Model New Line Old Line requirements

A $30 $50 50,000

B $25 $40 70,000

Production 80000 60000

line capacity.

Let

AN- Units of model A produced on the new production line

AO Units of model A produced on the old production line

BN Units of model B produced on the new production line

BO Units of model B produced on the old production line

Davison's objective is to determine the minimum cost production plan. The computer solution is shown in Figure 3.21.

a. Formulate the linear programming model for this problem using the following four constraints:

Constraint 1: Minimum production for model A

Constraint 2: Minimum production for model B

Constraint 3: Capacity of the new production line

Constraint 4: Capacity of the old production line

Solution :

Linear programming model:

Linear programming is defined as a mathematical model where the linear function is either minimize or maximize when they are subjected to some constraints.

The linear programming model is determined as follows :

Minimum : 30 AN + 50 AO + 25 BN + 40 BO

This is subject to the constraints as :

$AN+AO \geq 60,000$