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zheka24 [161]
2 years ago
6

Ellen drew a graph showing the solution to an inequality. A number line going from negative 1.25 to positive 0.75. An open circl

e is at negative 0.75. Everything to the left of the circle is shaded. Then she wrote four possible inequalities. 3.25 less-than 2.5 + r 3.25 greater-than 2.5 + r Negative 3.25 less-than negative 2.5 + r Negative 3.25 greater-than negative 2.5 + r Which inequality does Ellen’s graph show the solution to? 3.25 less-than 2.5 + r 3.25 greater-than 2.5 + r Negative 3.25 less-than negative 2.5 + r Negative 3.25 greater-than negative 2.5 + r
Mathematics
2 answers:
Lady bird [3.3K]2 years ago
5 0

Answer:

3.25 greater-than 2.5 + r

Step-by-step explanation:

It should be: r < 0.75

3.25 > 2.5 + r

r < 0.75

Sauron [17]2 years ago
3 0

Answer:

  Negative 3.25 greater-than negative 2.5 + r

Step-by-step explanation:

The solution Ellen drew is ...

  r < -0.75

This is the solution to ...

  -3.25 > -2.5 +r

  -0.75 > r . . . . . . . add 2.5 to both sides

_____

<em>Comment on the problem text</em>

Math expressions are much easier to read if you use math symbols to write them.

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Andrew deposits $300 into an account that earns 2% interest each year. After the first year, Andrew has $306 in the account. Aft
Sliva [168]

Answer:

It is a simple interest account

Step-by-step explanation:

As we might see from the given earnings, the amount of money he earned each year is the same as in the previous year. This means that the amount of money is growing linearly instead of exponentialy. This is characteristic to a simple interest account, which is found by using the formula:

I=Prt

where I = interest earned.

P = principal

r = Interest rate

t = time in years,

if we use this formula to calculate the amount of money earned after t years, we can see it will be the same as the values reported:

I=$300(0.02/year)(1year)=$6

I=$300(0.02/year)(2years)=$12

I=$300(0.02/year)(3years)=$18

So this simple interest account.

8 0
2 years ago
Which graph represents y=3 sqrt x+2
ziro4ka [17]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

y=3\sqrt{x+2}

Remember that the radicand must be greater than or equal to zero

so

x+2\geq 0

solve for x

subtract 2 both sides

x\geq -2

The domain is the interval [-2,∞)

All real number greater than or equal to -2

For x=-2

y=3\sqrt{-2+2}=0

so

The range is the interval [0,∞)

All real number greater than or equal to 0

Find the y-intercept

Remember that the y-intercept is the value of y when the value of x is equal to zero

For x=0

y=3\sqrt{0+2}

y=3\sqrt{2}

y=4.243

The y-intercept is the point (0,4.243)

therefore

The graph in the attached figure

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2 years ago
Your grade point average is 3.48. How can you write your grade point average as a fraction?
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Triangle A has a height of 2.5\text{ cm}2.5 cm2, point, 5, start text, space, c, m, end text and a base of 1.6\text{ cm}1.6 cm1,
konstantin123 [22]

Answer:

Option A

Option D

Option E

Step-by-step explanation:

we know that

If the height and base of triangle B are proportional to the height and base of triangle A

then

Triangle A and Triangle B are similar

Remember that

If two triangles are similar then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

so

\frac{h_A}{h_B} =\frac{b_A}{b_B}

where

h_A and h_B are the height of triangle A and triangle B

b_A and b_B are the base of triangle A and triangle B

In his problem we have

h_A=2.5\ cm\\b_A=1.6\ cm

substitute

\frac{2.5}{h_B} =\frac{1.6}{b_B}

Rewrite

\frac{2.5}{1.6} =\frac{h_B}{b_B}

\frac{h_B}{b_B}=1.5625

<u><em>Verify all the options</em></u>

A) we have

h_B=2.75\ cm\\b_B=1.76\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{2.75}{1.76}=1.5625

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

B) we have

h_B=9.25\ cm\\b_B=9.16\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{9.25}{9.16}=1.0098

The ratios are not equal

That means that are not proportional

therefore

These values could not be the height and base of triangle B

C) we have

h_B=3.2\ cm\\b_B=5\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{3.2}{5}=0.64

The ratios are not the same

That means that are not proportional

therefore

These values could not be the height and base of triangle B

D) we have

h_B=1.25\ cm\\b_B=0.8\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{1.25}{0.8}=1.5625

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

E) we have

h_B=2\ cm\\b_B=1.28\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{2}{1.28}=1.5625

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

8 0
2 years ago
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