Answer:
2. 13
Step-by-step explanation:
The least number of classes need for all of the students to be registered in a class is 13 since you want all of the stuednts to be registered so no one should be left out. If we do 12*12 (12 students in each class and there are 12 classes), that would only let 144 students take the swimming classes and 8 students would be left out. We don't want that though since we want all of the students to be registered. So let's go to 12*13 (12 students in each class and there are 13 classes), that would let 156 students take the swimming class. 156>152 so therefore, 13 classes would allow for all 152 students to be registered and it is the least number of classes needed for all the students to be registered in a class (plus you would have 4 seats left for anyone who wants to register in the future but the remainder doesn't matter).
Answer:
their sum: 2.8m
their difference: 1.2m
the third side's length should be smaller than their sum, larger than their difference
it could be: 1.3-1.4-1.5-1.6-1.7-1.8-1.9-2-2.1-2.2-2.3-2.4-2.5-2.6-2.7 but since it has to be a whole number, 2m is the only eligible answer.
It will have the same value. The slope of the mid-segment of DE is just equal to the slope of the segment of AC. This is because of the mid-segment theorem stating that both slopes of a triangle have same value. So the answer is -0.4 for both segments.
We are given the equation:
<span>Z(q) = 4q + ½ --->
1</span>
The equation for z(u + 1/2) is obtained by
substituting q with u + ½ in the equation, therefore we can say that:
<span>q = u + ½ --->
2</span>
Substituting this value into equation # 1:
Z = 4 (u + ½) + ½ = z (u + 1/2)
4 u + 2 + ½ = z (u + 1/2)
<span>Since it was given that z (u +
1/2) = ½ then,</span>
4 u + 2 + ½ = ½
4 u + 2.5 = 0.5
4 u = -2
u = -1/2 (ANSWER)
<span> </span>
So you have a right angle triangle. You need to use trig for this, as you have two values you can figure out a third.
You know that you have
90 deg. angle
19 deg. angle
Therefor you have 71 deg. angle
sin19 = x/15
15sin19 = x
x = 2.2
Now do Pythagoras c^2-b^2=a^2
a = 14.8
So the sides are 2.2 and 14.8 units long. (If these numbers are wrong tell me and I'll edit answer)
