Question

A rectangle has a height of 444 and a width of x^2+3x+2x 2 +3x+2x, squared, plus, 3, x, plus, 2. Express the area of the entire rectangle. Expression should be expanded. A rectangle has a height of 4 and a width of x squared + 3x + 2.

Answer 1

The area of the rectangle is $4x^2+12x+8$

Explanation:

Given that the height of the rectangle is 4.

The width of the rectangle is $x^2+3x+2$

Area of the rectangle:

The area of the rectangle can be determined using the formula,

$Area=height\times width$

where height = 4 and width = $x^2+3x+2$

Substituting the values in the above formula, we have,

$Area=4(x^2+3x+8)$

Let us expand the expression by multiplying the terms within the bracket, we get,

$Area=4x^2+12x+8$

Thus, the area of the entire rectangle is $4x^2+12x+8$

Answer 2

Answer:

x^3+7x^2+14x+8

Step-by-step explanation: