Answer:
The original water sample contains 830,000 cells per milliliter.
Explanation:
A sample of well water is tested for its bacterial content in a plate count assay. A one-milliliter sample of the water is diluted in a 1:10 dilution series. One milliliter of the fourth dilution tube is plated in a pour plate. After incubation, the plate has 83 colonies, indicating that the original water sample contained 830,000 cells per milliliter.
A because Only plant cells have chloroplasts
Answer:
A. Total Vit D intake = 1150000212 IU
B. Yes he met his RDA and does not need any supplements
C. 191666702%
Explanation:
I μg = 40 IU
1 oz = 28.35 g
I g = 1000000 μg
A. Low-fat Yoplait yogurt-2 μg = 2 * 40 IU = 80 IU
Cheerios cereal-1 μg = 40 1U
Coffee with milk-07μg = 0.7 * 40 = 28 IU
Turkey sandwich on whole-wheat bread with large garden salad-0.4 g = 0.4 * 1000000 * 40 IU = 16000000 IU Grilledd pork chop. 8 oz = 28.35 * 1000000 * 40 = 1134000000 IU
mashed potato and a side of gnled mixed vegetables-1.6 μg = 1.6 * 40 = 64 IU
Total vitamin D intake = 1150000212 IU of Vit D.
B. Since his RDA is 600 IU, he met his RDA and does not need any supplements of Vit D.
C. Percentage of his RDA Vit D intake = (1150000212/600) * 100% = 191666702 %