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KATRIN_1 [288]
2 years ago
14

According to Nasa, when the International Space Station (ISS) is at an altitude of 385 kilometers, it travels at about 27,707 ki

lometers per hour. After how many hours of travel will the ISS reach a star that is 4.8 lightyears away? Recall that 1 light year = 9.5 · 1012 kilometers and 1 kilometer = 0.62 miles. In your final answer, include all of your calculations.
Mathematics
2 answers:
Evgen [1.6K]2 years ago
4 0
Supposing the ISS travels at a constant speed, then use the relation,

t=space/velocity

Then you will obtain,

t=1.65\cdot 10^9\ hours
Genrish500 [490]2 years ago
4 0

Answer:

1.6457934818\times 10^9   hours

Step-by-step explanation:

ISS is at a distance = 385 km

We are supposed to find how many hours of travel will the ISS reach a star that is 4.8 light years away?

1 light year = 9.5 \times 10^{12}

So, 4.8 light years = 4.8 \times 9.5 \times 10^{12}

                               =4.56\times10^{13}km

So , we are supposed to find after how many hours ISS will be at an altitude 4.56\times 10^{13}km

We are also given that it travels at about 27,707 kilometers per hour

Since it travels 27707 km in hours = 1

So, it travels 1 km in hours = \frac{1}{27707}

It travels 4.56\times10^{13}km in hours = \frac{4.56\times10^{13}}{27707}

= 1.6457934818\times 10^9

Hence ISS will travel 1.6457934818\times 10^9 hours reach a star that is 4.8 light years away .  

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Now evaluate f(x) = 2x4 - 4x3-11x2+3x-6 for x=-2 f (-2) =
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2 years ago
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Sonbull [250]

Answer:cant really help with that because the question is messed up sorry

Step-by-step explanation:

6 0
2 years ago
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Given that line s is perpendicular to line t, which statements must be true of the two lines? Check all that apply.
artcher [175]
The basis to respond this question are:

1) Perpedicular lines form a 90° angle between them.

2) The product of the slopes of two any perpendicular lines is - 1.

So, from that basic knowledge you can analyze each option:

<span>a.Lines s and t have slopes that are opposite reciprocals.

TRUE. Tha comes the number 2 basic condition for the perpendicular lines.

slope_1 * slope_2 = - 1 => slope_1 = - 1 / slope_2, which is what opposite reciprocals means.

b.Lines s and t have the same slope.

FALSE. We have already stated the the slopes are opposite reciprocals.

c.The product of the slopes of s and t is equal to -1

TRUE: that is one of the basic statements that you need to know and handle.

d.The lines have the same steepness.

FALSE: the slope is a measure of steepness, so they have different steepness.

e.The lines have different y intercepts.

FALSE: the y intercepts may be equal or different. For example y = x + 2 and y = -x + 2 are perpendicular and both have the same y intercept, 2.

f.The lines never intersect.

FALSE: perpendicular lines always intersept (in a 90° angle).

g.The intersection of s and t forms right angle.

TRUE: right angle = 90°.

h.If the slope of s is 6, the slope of t is -6

FALSE. - 6 is not the opposite reciprocal of 6. The opposite reciprocal of 6 is - 1/6.

So, the right choices are a, c and g.
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5 0
2 years ago
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Dante's Mom wants to build a fence around their yard. Here are the measurements of the yard. What are the measurements of the mi
timama [110]

Answer:

(a)The missing measurements are 9 feet and 16\frac{1}{4}$ feet.

(b)Therefore, the length of the fence is  97\frac{1}{2}$ feet

Step-by-step explanation:

The diagram of the yard is attached below.

(a)I have labeled the missing dimensions of the yard as x and y.

Therefore:

y+8\frac{1}{4}=17 \frac{1}{4}\\y=17 \frac{1}{4}-8\frac{1}{4}\\y=9$ feet

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x+15\frac{1}{4}=31\frac{1}{2}\\x=31\frac{1}{2}-15\frac{1}{4}\\x=31-15+\frac{1}{2}-\frac{1}{4}\\x=16+\frac{1}{4}\\x=16\frac{1}{4}$ feet

The missing measurements are 9 feet and 16\frac{1}{4}$ feet.

(b)Length of the Fence

The fence is rectangular shaped with:

Length = 31\frac{1}{2}$ feet

Width = 17 \frac{1}{4}$ feet

Perimeter of a Rectangle = 2(L+W)

Therefore, the length of the fence

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