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KATRIN_1 [288]
2 years ago
14

According to Nasa, when the International Space Station (ISS) is at an altitude of 385 kilometers, it travels at about 27,707 ki

lometers per hour. After how many hours of travel will the ISS reach a star that is 4.8 lightyears away? Recall that 1 light year = 9.5 · 1012 kilometers and 1 kilometer = 0.62 miles. In your final answer, include all of your calculations.
Mathematics
2 answers:
Evgen [1.6K]2 years ago
4 0
Supposing the ISS travels at a constant speed, then use the relation,

t=space/velocity

Then you will obtain,

t=1.65\cdot 10^9\ hours
Genrish500 [490]2 years ago
4 0

Answer:

1.6457934818\times 10^9   hours

Step-by-step explanation:

ISS is at a distance = 385 km

We are supposed to find how many hours of travel will the ISS reach a star that is 4.8 light years away?

1 light year = 9.5 \times 10^{12}

So, 4.8 light years = 4.8 \times 9.5 \times 10^{12}

                               =4.56\times10^{13}km

So , we are supposed to find after how many hours ISS will be at an altitude 4.56\times 10^{13}km

We are also given that it travels at about 27,707 kilometers per hour

Since it travels 27707 km in hours = 1

So, it travels 1 km in hours = \frac{1}{27707}

It travels 4.56\times10^{13}km in hours = \frac{4.56\times10^{13}}{27707}

= 1.6457934818\times 10^9

Hence ISS will travel 1.6457934818\times 10^9 hours reach a star that is 4.8 light years away .  

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In ADEF, f = 610 inches, e = 590 inches and ZE=70°. Find all possible values of ZF,
Elina [12.6K]

Answer:

"76°" is the appropriate solution.

Step-by-step explanation:

Please find attachment of the diagram according to the given query.

The given values are:

In ΔDEF,

f = 610 inches

e = 590

∠E = 70°

∠F = ?

By using the law of sines, we get

⇒  \frac{Sin E}{e} =\frac{Sin  F}{f}

On substituting the values, we get

⇒  \frac{Sin70^{\circ}}{590} =\frac{SinF}{610}

On applying cross multiplication, we get

⇒   SinF=\frac{610\times Sin 70^{\circ}}{590}

On substituting the values, we get

⇒            =\frac{61\times 0.95969262}{59}

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