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Aleksandr [31]
2 years ago
6

Curious Carl conducted an experiment on the eating habits of black bears. While living in the woods, Carl was able to record the

daily diet of five bears. After a year of observation, Carl summarized his findings in the graph. Which statement is an observation rather than an inference?
Chemistry
2 answers:
kvv77 [185]2 years ago
7 0

Answer:

A

Explanation:

так показано в графике

Gnom [1K]2 years ago
6 0

Answer:

B

Explanation:

I just got it correct.

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What happens during a mosquito 6 chromosomes to form eggs.
lbvjy [14]
<span>Since the diploid number of mosquitoes is six, that means that there are 6 chromosomes in every somatic (non-reproductive) cell,including the cells that make up the stomach.The six chromosomes represent two three-chromosome sets the mosquito received one set of three chromosomes from the egg cell of the mother and a similar set of three chromosomes from the sperm cell of the father.</span>
7 0
2 years ago
Urea is a common fertilizer with the formula CO(NH2)2 that is sometimes used as a chemical de-icer for icy road surfaces in the
nordsb [41]

Answer:

The answer to your question is  molality = 0.61

Explanation:

Freezing point is the temperature at which a liquid turns into a solid if a solute is added to a solution, the freezing point changes.

Data

Kf = 1.86 °C/m

molality = ?

ΔTc = 1.13°C

Formula

ΔTc = kcm

Solve for m

m = ΔTc/kc

Substitution

m = 1.13 / 1.86

Simplification and result

m = 0.61

4 0
2 years ago
Two sets of flasks are connected by a hollow copper pipe, as shown. Which set will change the temperature most quickly?
Dennis_Churaev [7]
Hmm. I'm not 100% sure but. I'm pretty sure it's A because the heated water is below and there's a hotter temp. Also because it's copper, heat will move more quickly. I'm not 100% sure, are there notes you can check?
8 0
2 years ago
Read 2 more answers
Calculate the cell potential E at 25°C for the reaction 2 Al(s) + 3 Fe2+(aq) → 2 Al3+(aq) + 3 Fe(s) given that [Fe 2+] = 0.020 M
Elodia [21]

Answer:

1.18 V

Explanation:

The given cell is:

Al(s)/Al^{3+}(0.10M)||Fe^{2+}(0.020M)/Fe(s)

Half reactions for the given cell follows:

Oxidation half reaction: Al(s)\rightarrow Al^{3+}(0.10M)+2e^-;E^o_{Al^{3+}/Al}=-1.66V

Reduction half reaction: Fe^{2+}(0.020M)+2e^-\rightarrow Fe(s);E^o_{Fe^{2+}/Fe}=-0.45V

Multiply Oxidation half reaction by 2 and Reduction half reaction by 3

Net reaction: 2Al(s)+3Fe^{2+}(0.020M)\rightarrow 2Al^{3+}(0.10M)+3Fe(s)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=-0.45-(-1.66)=1.21V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Al^{3+}]^2}{[Fe^{2+}]^3}

where,

E_{cell} = electrode potential of the cell = ?V

E^o_{cell} = standard electrode potential of the cell = +1.21 V

n = number of electrons exchanged = 6

Putting values in above equation, we get:

E_{cell}=1.21-\frac{0.059}{6}\times \log(\frac{0.10^2}{0.020^3})\\\\E_{cell}=1.18V

5 0
2 years ago
Ethyne (C2 H2 (g), mc032-1.jpgHf = 226.77 kJ/mol) undergoes complete combustion in the presence of oxygen to produce carbon diox
Gnesinka [82]
2 C2H2 + 5 02  >  4 CO2 + 2 H2O

Products  - Reactants ( all units are kJ/mo1):

(4 x -393.5) + (2 x -241.82) - (2 x 226.77) - (5 x 0) = -2511.2 kJ/mo1

-2511.2 kJ/mo1 is for 2 moles of C2H2.The question asked for 1 mole of C2H2, so: -2511.2 / 2 = -1255.6 kJ/mo1

answer: -1255.6 kJ/mo1
3 0
2 years ago
Read 2 more answers
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