Answer:
C. 81 degrees Celsius
Explanation:
- To solve this problem, we can use the relation:
<em>Q = m.c.ΔT,</em>
where, Q is the amount of heat released from water (Q = - 1200 J).
m is the mass of the water (m = 20.0 g).
c is the specific heat capacity of water (c of water = 4.186 J/g.°C).
ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = final T - 95.0°C).
<em>∵ Q = m.c.ΔT</em>
∴ (- 1200 J) = (20.0 g)(4.186 J/g.°C)(final T - 95.0°C ).
(- 1200 J) = 83.72 final T - 7953.
∴ final T = (- 1200 J + 7953)/83.72 = 80.67 °C ≅ 81.0 °C.
<em>So, the right choice is: C. 81 degrees Celsius
</em>
<em></em>
Answer:
The volume when the pressure is changed to 1.23 atm and temperature is constant will be <u><em>6.3075 L</em></u>.
Explanation:
Pressure and volume are related by Boyle's law that says:
"The volume occupied by a certain gas mass at a constant temperature is inversely proportional to the pressure"
Boyle's law is expressed mathematically as:
P * V = k
where:
- P: Pressure
- V: Volume
- k: Constant
Assuming a certain volume of gas V1 is at a pressure P1 at the beginning of the experiment. By varying the volume of gas to a new V2 value, then the pressure will change to P2, and the following will be true:
P1 * V1 = P2 * V2
In this case you have:
- P1= 754 torr= 0.9921 atm (1 atm=760 torr)
- V1= 7.82 L
- P2=1.23 atm
- V2=?
Replacing:
0.9921 atm*7.82 L=1.23 atm*V2
Resolving:
V2≅6.3075 L
<u><em>The volume when the pressure is changed to 1.23 atm and temperature is constant will be 6.3075 L.</em></u>
The question is incomplete, the complete question is;
Suna passes an electric current through a sample of clear, colorless, and odorless liquid. As the experiment continues, bubbles form, and the volume of liquid decreases. Suna collects samples of two colorless, odorless gases that bubble out of the liquid. One of the gases burns. Neither the original liquid nor the other gas burns. Which is the best explanation of her results? The electric current changed some of the sample to gas even though the sample was not breaking down. Therefore, the original liquid is a compound. The electric current released a gas that was odorless and colorless, like the original sample. Therefore, the original liquid is an element. The sample was broken down by the electric current and formed a new substance that could burn. Therefore, the original liquid is a compound. The sample lost some of its volume, but the gas still had the same chemical makeup as the original sample. Therefore, the original liquid is an element.
Answer:
The sample was broken down by the electric current and formed a new substance that could burn. Therefore, the original liquid is a compound.
Explanation:
When electric current is passed through a compound, the compound may become broken down to release its constituents. We refer to this phenomenon as electrolysis. We can now say that the substance has been 'decomposed' electrolytically.
Since the original sample was decomposed to yield a gas that could burn and one that couldn't burn even though the original sample couldn't burn, then the original sample is a compound.
M=D*V
D=620 g/cm³
V=75 cm³
m= 620 g/cm³ * 75 cm³=46500 g
m=46500g
Answer:
483.27 minutes
Explanation:
using second faradays law of electrolysis
