Quadratic equation: ax² + bx + c =0
x' = [-b+√(b²-4ac)]/2a and x" = [-b-√(b²-4ac)]/2a
6 = x² – 10x ; x² - 10x -6 =0
(a=1, b= - 10 and c = - 6
x' = [10+√(10²+4(1)(-6)]/2(1) and x" = [10-√(10²+4(1)(-6)]/2(1)
x' =5+√31 and x' = 5-√31
Think of sqrt(2) as a variable.
3x - x = 2x
If x = sqrt(2), then answer is 2sqrt(2)
Answer:
option: B is correct
A reflection across line n followed by a 270° rotation about point P.
Step-by-step explanation:
Clearly from the figure we could see that the graph is first reflected across the given line n such that we obtain the figure R'S'T'V'U' and then it is rotated 270° across the point P so that we obtain the figure R"S"T"U"V".
Hence, option B is correct.
( A reflection across line n followed by a 270° rotation about point P )
Answer:24,942,060
Step-by-step explanation:
(10,10,4) - (3,2,0) = 7,8,4
7+8+4=19
19!/(7!*8!*4!)= 24'942'060
