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lilavasa [31]
2 years ago
10

A large television company (CFR) contacts a technology provider, GET, Inc., to arrange a meeting to discuss an upgrade of its ex

isting server network. At the meeting, a representative of GET draws up plans for the new servers, along with required modifications of the existing storage structures. On December 1, the president of CFR received a signed letter from GET's sales agent, offering to install the new servers at the cost of $5 million. The letter included provisions for delivery, installation, warranties, and payment terms. However, the letter did not address any method of formal acceptance of the offer. CFR's president immediately decided to accept the offer, telephoning the sales agent for confirmation, however, the agent was out of town. The president left a message for agent stating, "This looks good. I'm sold. Give me a call back when you can." She further ordered her construction team to get started on the modifications. Later that week, news broke of the passage of a law which heavily taxed technology providers. After receiving the news, GET sent out a mass email notifying all of its clients and potential clients that "all current offers were now revoked, and any agreements going forward would be 50 percent higher than currently quoted." What are the arguments you would make as the president of CFR
Engineering
1 answer:
ELEN [110]2 years ago
8 0

Answer:

In the passage, it has been mentioned that the president of CFR received the letter from GET, who offered them to install the network servers at the cost of $5 million and the president of CFR also accept it. Although the GET will charge 50 percent more charges after getting the news of heavy tax on technology providers, I will not accept it. As a president of CFR my argument will be that I will ask them (GET) to install the servers at the earlier price that the GET offers before heavy taxation, otherwise, I will reject the offer as I had not formally agreed. Because, the president already informed them about the acceptance of the offer.

My other argument will be that if the GET will not accept my previous proposal, I will go to another technology provider, who can offer the service at a lower cost in comparison to the GET.

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A shaft consisting of a steel tube of 50-mm outer diameter is to transmit 100 kW of power while rotating at a frequency of 34 Hz
nikitadnepr [17]

Answer:

25 - \sqrt[4]{26.66*10^{-8} }  mm

Explanation:

Given data

steel tube : outer diameter = 50-mm

power transmitted = 100 KW

frequency(f) = 34 Hz

shearing stress ≤ 60 MPa

Determine tube thickness

firstly we calculate the ; power, angular velocity and torque of the tube

power = T(torque) * w (angular velocity)

angular velocity ( w ) = 2\pif = 2 * \pi * 34 = 213.71

Torque (T) = power / angular velocity = 100000 / 213.71 = 467.92 N.m/s

next we calculate the inner diameter  using the relation

  \frac{J}{c_{2}  } = \frac{T}{t_{max} }  = 467.92 / (60 * 10^6) =  7.8 * 10^-6 m^3

also

c2 = (50/2) = 25 mm

\frac{J}{c_{2} } = \frac{\pi }{2c_{2} } ( c^{4} _{2} - c^{4} _{1} ) =  \frac{\pi }{0.050} [ ( 0.025^{4} - c^{4} _{1}  ) ]

therefore; 0.025^4 - c^{4} _{1} = 0.050 / \pi (7.8 *10^-6)

c^{4} _{1} = 39.06 * 10 ^-8 - ( 1.59*10^-2 * 7.8*10^-6)

    39.06 * 10^-8 - 12.402 * 10^-8 =26.66 *10^-8

c_{1} = \sqrt[4]{26.66 * 10^{-8} }  =

THE TUBE THICKNESS

c_{2} - c_{1} = 25 - \sqrt[4]{26.66*10^{-8} }  mm

4 0
2 years ago
Superheated steam at an average temperature 200 C is transported through a steel pipe (k=50 W/mK, D_0=8.0 cm,D_i=6.0 cm,and L=20
Zarrin [17]

The total amount of daily heat transfer is 1382.38 M w.

The temperature on the outside surface of the gypsum plaster insulation is 17.96 ° C.

<u>Explanation:</u>

Given data,

T_{\infty} = 10° C

h_{0} = 250 w/ m^{2} k

Pipe length = 20 m

Inner diameter d_{1} = 6 cm, r_{1} = 3 cm

Outer diameter d_{2} = 8 cm, r_{2} = 4 cm

The thickness of insulation is 4 cm.

r_{3} = r_{2} + 4

= 4+4

r_{3} = 8 cm

h_{0} is the heat transfer coefficient of  convection inside, h_{i} is the heat transfer coefficient of  convection outside.

The heat transfer rate between ambient and steam is

q=\frac{T_{S}-T_{\infty}}{\frac{1}{h_{i}\left(2 \pi r_{1} L\right)}+\frac{\ln \left(r_{2} / r_{1}\right)}{2 \pi K_{1} L}+\frac{\ln \left(r_{3}/ r_{2}\right)}{2 \pi K_{2} L}+\frac{1}{h_{0}\left(2 \pi r_{3} L\right)}} watt

=  \begin{aligned}&\frac{1}{800(2 \pi x \cdot 03 \times 20)}\++\frac{\ln (4 / 3)}{2 \pi \times 50 \times 20}+\frac{\ln (8 / 4)}{2 \pi \times 0.5 \times 20}+\frac{1}{200(2 \pi x \cdot 08 \times 20)}\end{aligned} watt

= \frac{190}{0.0003317+0.0000458+0.0110+0.0004976} watt

q = 15999.86 watt

The total amount of daily heat transfer = 15999.86 × 86400

= 1382.387904 watt

= 1382.38 M w

The total amount of daily heat transfer is 1382.38 M w.

b) The temperature on the outside surface of the gypsum plaster insulation.

q = \frac{T_{3}-T_{\infty}}{\frac{1}{\ln \left(2 \pi \ r_{3} L\right)}}

15999.86   =\frac{\frac{1}{T_3}-10}{\frac{1}{200(2 \pi . 08 \times 20)}}

T_{3} - 10 = 7.96

T_{3} = 17.96 ° C.

4 0
2 years ago
Raul doesn’t feel like he needs to write down events that will happen months from now. Explain to him why it is important to use
MAXImum [283]
The primary reason for having a calendar is to organize the days, weeks, months and years. It keeps a track of which day of the week events fall and when special events are going to happen. Historically speaking calendars were often uses to preserve religious holidays and events.
4 0
2 years ago
Read 2 more answers
Rigid bar ACB is supported by an elastic cir-cular strut DC having an outer diameter of 15 in. and inner diameter of 14.4 in. Th
Ne4ueva [31]

Answer:

The change in length of the circular strut DC = 0.0028 in.

The vertical displacement of the rigid bar at point B = 0.00378 in.

Explanation:

We have the following parameters or information in the question given above:

=> The outer diameter = 15 in., the inner diameter = 14.4 in., the modulus elasticity of E = 29,000 ksi, and the Point load P = 5kips.

The diagram showing the rigid bar ACB is supported by an elastic cir-cular strut DC  is given in  the attached picture below.

According to Newton's law of motion, it can be seen that the force on CD, that is FCD is equal and opposite to ACD. Hence, FCD = ACD.

Where FCD = p × [4 + 5] ÷ [sin Ф × 4].

kindly note that from the diagram sin Ф = 3/5, cos Ф = 4/5 and tan Ф = 3/4. Also p =5.

Hence, FCD =[ 5 × 9] ÷ [3/5 × 4] = 18.75 kip. So FCD = ACD.

The next thing here is to determine the area and length of CD, say the area of CD is G, thus, G = π/4 × [ 15² - 14.4²] = 13.854 in².

The lenght of CD is = √[4² + 3²] = √[16 + 9] = 5ft. Thus, 5 × 12 = 60in.

Hence, the change in length of the circular strut DC = [18.75 × 60] ÷ 13.854 × 29000 = 0.0028 in.

The vertical deflection of CD = 0.0028 × 3/5 = 0.00168 in.

We have that; 4 /CV = 9BV. Hence, BV = 9/4× CV.

(CV = vertical deflection of CD).

The vertical displacement of the rigid bar at point B = 9/ 4 × 0.00168 in = 0.00378 in.  

7 0
2 years ago
During an experiment conducted in a room at 25°C, a laboratory assistant measures that a refrigerator that draws 2 kW of power h
zvonat [6]

Answer:

Not reasonable.

Explanation:

To solve this problem it is necessary to take into account the concepts related to the performance of a reversible refrigerator. The coefficient of performance is basically defined as the ratio between the heating or cooling provided and the electricity consumed. The higher coefficients are equivalent to lower operating costs. The coefficient can be greater than 1, because it is a percentage of the output: losses, other than the thermal efficiency ratio: input energy. For a reversible refrigerator the coefficient is given by

COP_{R,rev} = \frac{1}{\frac{T_1}{T_2}-1}

Where,

T_1 =High temperature

T_2 =Low Temperature

With our values previous given we can find it:

T_2 = -30\°C = (-30+273)

T_2 = 243K

T_1 = 25\°C = (25+273)

T_1 = 298K

With these values we can now calculate the coefficient of performance:

COP_{R,rev} = \frac{1}{\frac{298}{243}-1}

COP_{R,rev} = 4.42

At the same time we can calculate the work consumption of the refrigerator, this is

W = \dot{W}\Delta t

Where,

\dot{W} = Required power input

t = time to remove heat from a cool to water medium

W = 2kJ/s * 20 min

W = 2kJ/s * 1200s

W = 2400kJ

In this way we can calculate the coefficient of the refrigerator directly:

COP_R = \frac{Q_L}{W}

Where,

Q = Amoun of heat rejected

COP_R = \frac{30000}{2400}

COP_R = 12.5

Comparing the values of both coefficients we have that the experiments are NOT reasonable, because the coefficient of a refrigerator is high compared to  coefficient of reversible refrigerator.

5 0
2 years ago
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