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diamong [38]
2 years ago
5

Previously, an organization reported that teenagers spent 4.5 hours per week, on average, on the phone. The organization thinks

that, currently, the mean is higher. Fifteen randomly chosen teenagers were asked how many hours per week they spend on the phone. The sample mean was 4.75 hours with a sample standard deviation of 2.0. Conduct a hypothesis test, the Type I error is:
a. to conclude that the current mean hours per week is higher than 4.5, when in fact, it is higher
b. to conclude that the current mean hours per week is higher than 4.5, when in fact, it is the same
c. to conclude that the mean hours per week currently is 4.5, when in fact, it is higher
d. to conclude that the mean hours per week currently is no higher than 4.5, when in fact, it is not higher
Mathematics
1 answer:
hammer [34]2 years ago
6 0

Answer:

Type I error is : to conclude that the current mean hours per week is higher than 4.5, when in fact, it is the same.

Step-by-step explanation:

We are given that an organization reported that teenagers spent 4.5 hours per week, on average, on the phone. The organization thinks that, currently, the mean is higher. For this fifteen randomly chosen teenagers were asked how many hours per week they spend on the phone. The sample mean was 4.75 hours with a sample standard deviation of 2.0 hours.

Let Null Hypothesis, H_0 : \mu \leq 4.5 hours {means that the current mean hours per week is less than or equal to 4.5}

Alternate Hypothesis, H_1 : \mu > 4.5 hours {means that the current mean hours per week is higher than 4.5}

<em>Now, T</em><u><em>ype I error states that</em></u><em> : Probability of rejecting null hypothesis given the fact that it was true or Rejecting the true null hypothesis.</em>

<u>So, according our question;</u>

Type I error is to conclude that the current mean hours per week is higher than 4.5, when in fact, it is the same.

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Kim drove 627 miles in 9.5 hours. What is
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Answer:

Step-by-step explanation:

66 mile per hour .

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2 years ago
The Naturally Made Bath and Body store pays $550 a month for rent and utilities. The average cost for its products to be manufac
Lilit [14]

Answer:

220 products need to be sold to break it even.

Step-by-step explanation:

550 + 3.00x = 5.50x

550 = 2.50x

220 = x

6 0
2 years ago
Read 2 more answers
A software store has put some of its inventory on sale. Games are marked down by 15%, and security programs are marked down by 1
Katyanochek1 [597]

Answer:

Option D. \$11.34

Step-by-step explanation:

Let

x -----> the original price of one game

y ----> the original price of one security programs

Remember that

100\%-15\%=85\%=85\100=0.85

100\%-18\%=82\%=82\100=0.82

The total pay with discount is

\$35.70+\$22.96=\$58.66

we have that

0.85(2x)=35.70\\1.70x=35.70\\x=\$21

0.82y=22.96\\y=\$28

Find the total pay without discount

2x+y=2(21)+28=\$70

The amount saved is the difference

\$70-\$58.66=\$11.34

5 0
2 years ago
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Pedro has created the function f(x)= 4x-3/2 to represent the number of assingments he has completed where x represents the numbe
Law Incorporation [45]
The given function is
f(x) = 4x - 3/2
where
f(x) = number of assignments completed
x =  number of weeks required to complete the assignments

We want to find f⁻¹ (30) as an estimate of the number of weeks required to complete 30 assignments.
The procedure is as follows:

1. Set y = f(x)
   y = 4x - 3/2

2. Exchange x and y
   x = 4y - 3/2

3. Solve for y
   4y = x + 3/2
   y = (x +3/2)/4

4. Set y equal to f⁻¹ (x)
  f⁻¹ (x) = (x + 3/2)/4

5. Find f⁻¹ (30)
  f⁻¹ (30) = (30 + 3/2)/4 = 63/8 = 8 (approxmately)

Answer:
Pedro needs about 8 weeks to complete 30 assignments.

6 0
2 years ago
A distribution for a set of wrist circumferences (measured in centimeters) taken from the right wrist of a random sample of newb
lozanna [386]

Answer:

A Histogram will be used to represent the size of right wrist of the random sample of newborn infants.

Step-by-step explanation:

A histogram is the graphical representation of the frequency distribution in the given sample. As the value of circumference can be a positive real number, therefore a Histogram with class boundaries can be formed such that the overall frequency of a wrist size is also visible in the graph.

Also as the distribution will be of continuous nature thus a histogram is a more suitable option as compared to a bar or stem and leaf graph.

3 0
2 years ago
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