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Ymorist [56]
2 years ago
13

Harry had $32. He spent all the money on buying 3 notebooks for $x each and 4 packs of index cards for $y each. If Harry had bou

ght 5 notebooks and 5 packs of index cards, he would have run short of $18.
A student concluded that the price of each notebook is $5 and the price of each pack of index cards is $1. Which statement best justifies whether the student's conclusion is correct or incorrect?

The student's conclusion is incorrect because the solution to the system of equations 3x + 4y = 32 and 5x + 5y = 50 is (8, 2).
The student's conclusion is incorrect because the solution to the system of equations 3x + 4y = 32 and 5x + 5y = 18 is (8, 2).
The student's conclusion is correct because the solution to the system of equations 3x + 4y = 32 and 5x + 5y = 18 is (5, 1).
The student's conclusion is correct because the solution to the system of equations 3x − 4y = 32 and 5x − 5y = 50 is (5, 1).
Mathematics
1 answer:
LenKa [72]2 years ago
4 0
3x + 4y = 32....multiply by 5
5x + 5y = 50...multiply by -3
---------------
15x + 20y = 160 (result of multiplying by 5)
-15x - 15y = -150 (result of multiplying by -3)
--------------add
5y = 10
y = 10/5
y = 2

3x + 4y = 32
3x + 4(2) = 32
3x + 8 = 32
3x = 32 - 8
3x = 24
x = 24/3
x = 8

solution (8,2)

The students conclusion is incorrect......it is answer choice 1



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Jillian is selling boxes of cookies to raise money for her basketball team. The 10 oz. box costs $3.50, while the 16 oz. box cos
RideAnS [48]

Answer:

Jillian sold 15 ten-oz bags and 9 sixteen-oz bags.

Step-by-step explanation:

Let x represent number of 10-oz bags and y represent number of 16-oz bags.

We have been given that Jillian sold 24 boxes of cookies in total. We can represent this information in an equation as:

x+y=24...(1)

We are also told that 10 oz. box costs $3.50, while the 16 oz. box costs $5.00, so the cost of x 10-oz bags would be 3.50x and cost of y 16-oz bags would be 5y.

At the end of one week, she collected $97.50. We can represent this information in an equation as:

3.5x+5y=97.50...(2)

Now, we will use substitution method to solve our system of equations. From equation (1), we will get:

y=24-x

Substitute this value in equation (2):

3.5x+5(24-x)=97.50

3.5x+120-5x=97.50

-1.5x+120=97.50

-1.5x+120-120=97.50-120

-1.5x=-22.5

\frac{-1.5x}{-1.5}=\frac{-22.5}{-1.5}

x=15

Therefore, the number of 10-oz boxes sold be Jillian is 15.

Now, we will substitute x=15 in equation (1) to solve for y.

15+y=24

15-15+y=24-15

y=9

Therefore, the number of 16-oz boxes sold be Jillian is 9.

8 0
2 years ago
Mr. Wilson is giving his students a vocabulary test tomorrow over all the terms they have learned from this semester. Today, he
Eddi Din [679]
1) The population

Is the set of all the terms that the teacher taught this semester and which he wrote down on the note cards and put in the paper bag.

2) The sample is every set of five cards that is selected by each student.

3) I think the sample is representative because all ther terms have the same probability of being selected. 

Further, given that the cards are replaced every time all the students will face the same population when they are going to select a sample.
<span><span>Comments </span> <span>Report</span></span>
8 0
2 years ago
T= 300 (d−15) 2 ​ +20space, T, equals, start fraction, left parenthesis, d, minus, 15, right parenthesis, start superscript, 2,
stealth61 [152]

As can be read from your statement written "T, equals, start fraction, left parenthesis, d, minus, 15, right parenthesis, strt superscript, 2, end superscript, divided by, 300, end fraction, plus, 20", I hope your model equation is this :

T = \frac{(d-15)^{2}}{300}  + 20

Hope this is your question, if not I think you will, still be able to find an answer of your question based on this solution

As we have to find lowest average temperature, So for minimum of a function its derivative is equal to 0 there.

So lets find derivative of T function first

So first expand (d-15)^{2} as (d-15)(d-15)

we will use FOIL to multiply these

so (d-15)(d-15) = d^{2} -15d -15d +225

= d^{2} -30d +225

so we have T = \frac{d^{2} -30d +225}{300} +20

Now we will derivate each term here,300 in denominator is constant so that will come as it in in denominator.

To derivate terms in dx^{2} -30d +225 we will use power rule formula:

(x^{n} )'= nx^{n-1}

so derivative of (d^{2} )'= 2d^{2-1} = 2d^{1} = 2d

Then derivative of d will be 1

so that of -30d will be -30

then derivate of constant -225 will be 0

so we will have derivative as \frac{2d-30}{300} for the fraction part and then derivative of +20 is again 0 as its constant term

T' = \frac{2d-30}{300}

For minimum we will put this derivative =0

0 = \frac{2d-30}{300}

Now solve for d

times both sides by 300

0 \times 300 = \frac{2d-30}{300} \times 300

0 = 2d-30

0 +30 = 2d -30 +30

30 = 2d

\frac{30}{2} = \frac{2d}{2}

15 = d

So now we have to find value of lowest temperature.

For that simply plug 15 in d place in original T function equation

T = \frac{(d-15)^{2}}{300}  + 20

T = \frac{(15-15)^{2}}{300}  + 20

T = 20

So T = 20 °C is the lowest average temperature and the answer.

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6 0
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