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Katyanochek1 [597]
2 years ago
14

Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then

the following is true. ∂P ∂y = ∂Q ∂x ∂P ∂z = ∂R ∂x ∂Q ∂z = ∂R ∂y . Since F is conservative, there exists a function f such that F = ∇f, that is, P, Q, and R are defined as follows. (Enter your answers in the form fx, fy, fz.) P = Q = R = Since P, Q, and R have continuous first order partial derivatives, says that ∂P/∂y = fxy = fyx = ∂Q/∂x, ∂P/∂z = fxz = fyx = ∂ARE/∂x, and ∂Q/∂z = fyx = fxy = ∂R/∂y.

Mathematics
1 answer:
GrogVix [38]2 years ago
5 0

Answer:

Answer with steps is in the following attachments

Step-by-step explanation:

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Answer:

5.83

Step-by-step explanation:

Find the mean:

10(.1) + 15(.2) + 20(.2) + 25(.4) + 3-).1)

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Find the standard deviation:

\sqrt{(10 -21)x^{2} (.1) + (15 -21)x^{2} (.2)+(20-21)x^{2} (.2)+(25-21)x^{2} (.4)+(30-21)x^{2} (.1)}= 5.83

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Answer:

The confidence interval for the difference in proportions is

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Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

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<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

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The correct answer to this question is that "<span>The experimental probability is 1/15 less than the theoretical probability."

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</span>
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