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borishaifa [10]
2 years ago
12

At barlow school ,4/9 of the 873 students are boys

Mathematics
2 answers:
Maksim231197 [3]2 years ago
8 0

Answer:

=Barlow by 181 boys

Step-by-step explanation:

lets calculate the no of boys in Barlow

=4/9×873=388

388 boys

in Willow school

to bet no of boys

3/3-2/3=1/3

1/3×620=207(in a calculator it will give you decimals so i rounded of to the nearest whole no.)

388-207=181

Dafna11 [192]2 years ago
7 0

Answer:

BARLOW SCHOOL has 388 boys

WILLOW SCHOOL has 207 boys

Barlow school has the highest number of boys with 181 boys

Step-by-step explanation:

To compare between schools having the greater number of boys and by how many, it would be best if we interpret CLEARLY all information supplied.

Let's begin:

BARLOW SCHOOL:

Number of boys = 4/9 of 873

Number of boys = 4/9 * 873

= 4 * 97

Number of boys = 388.

Barlow school have 388 boys

WILLOW SCHOOL

At Willow school, 2/3 of 620 are girls.

We can get to the number of boys two ways here.

2/3 of 620

= 2/3 * 620

= 2 * 206.67

= 413.34 (somehow we need to Approximate this value.?

Number of girls = 413.

To get the number of boys, we subtract the number of girls from the total number of students.

Number of boys = 620 - 413

= 207

OR

1 - ⅔ = ⅓

= ⅓ * 620

= 206.67

Number of boys = 207 (Appropriately)

FROM ALL WE'VE CALCULATED, we'll see that:

BARLOW SCHOOL has 388 boys

WILLOW SCHOOL has 207 boys

Difference between the number of boys in both school:

388 - 207 = 188

Barlow school has the highest number of boys with 181 boys

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A college admissions office uses the following equation to predict the grade point average of an incoming student:

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Answer:

In case (a) car makes 105° turn.

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In case (c) car makes 105° turn.

Step-by-step explanation:

Figure is redrawn To explain properly (in attachment)

Given : streets are parallel means \overline{AB} ║ \overline{CD},

             AB - 4th street , CD - 3rd street and XY - King Ave.

            ∠XLA = 75°

To find : (a) ∠XLB

              (b) ∠LMD (left onto 3rd streat means left of car)

              (c) ∠YMD (right means right side of car)

∠XLB + ∠XLA = 180° (Linear Pair = 2 adjacent angles are  

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∠XLB + 75° = 180°

∠XLB  = 180 - 75

∠XLB = 105°

∴ In case (a) car makes 105° turn.

∠LMD = ∠XLA = 75° (Corresponding angles of parallel lines are equal)

∠LMD = 75°

∴ In case (b) car makes 75° turn.

∠YMD + ∠LMD = 180° (Linear Pair = 2 adjacent angles are

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∠YMD + 75° = 180°

∠YMD = 180 - 75

∠YMD = 105°

∴In case (c) car makes 105° turn.

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