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GalinKa [24]
2 years ago
12

The kinetic energy K (in joules) of a falling apple is represented by K=v22, where v is the speed of the apple (in meters per se

cond). How fast is the apple traveling when the kinetic energy is 32 joules? The apple is traveling at meters per second.
Mathematics
1 answer:
Serggg [28]2 years ago
5 0

Answer: 1.455 m/s

Step-by-step explanation: k = 22v defines the motion of falling apple.

With k as kinetic energy and v as velocity.

We are to find the value of v at k = 32 joules

32 = 22v

v = 32/ 22

v = 1.455 m/s

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