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Anvisha [2.4K]
2 years ago
12

A bug was running along a number line at a speed of 11 units per minute. It never changed its direction. If at 7:15 pm it was at

point 100, where could it be at 7:20 pm?
Mathematics
2 answers:
Minchanka [31]2 years ago
8 0

Answer:

155 Units

Step-by-step explanation:

Rate of Bug (given) = 11 units PER MINUTE

It never changed direction, so it was going in positive direction (assume).

In 7:15 pm (evening), it was at Point 100,

We want the point at which it was at 7:20 pm.

7:20pm - 7:15pm = 5 minutes

So, time passed 5 minutes. It's rate is 11 units PER MINUTE, so in 5 mins:

11 * 5 = 55 units

<em>Assuming he is going in positive direction</em>, the bug will be at:

100 + 55 = <u>155 Units</u>

murzikaleks [220]2 years ago
6 0

Answer:

155 units and 45 units

Step-by-step explanation:

7:20-7:15=5

5+50=55

100+55=155

100-45=55

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<h3><u>Question:</u></h3>

In math class, Sam correctly multiplied 3.625×10-8 by 500, then reported his product in scientific notation. What was the exponent in Sam’s product? A -16 B -10 C -7 D -5

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