Answer: B - <span>The sale price is always less than the original price.</span><span>
$7.99 > $5.59
$10.99 </span>> <span>$7.69
$12.99 </span>> <span>$9.09
$15.99 </span>> <span>$11.19
$24.99 </span>> <span>$17.49
$29.99 </span>> $20.99
Answer:
11 boxes
Step-by-step explanation:
multiply 3 by 12 then add the product of that to 96 pens then divide the sum which is 132 by 12 and you should get 11.
Answer:
The size of Harry's loan is $9000.
Step-by-step explanation:
D(t) models Harry's remaining debt, in dollars, as a function of time t, in months that is given by :

We can see 200 is in negative that means it is getting deducted from the function. So, Harry must be paying this each month against his loan.
Lets put t = 0, that shows no payments have been made.
This will get the amount of loan, before any payments.

So,
Hence, the size of Harry's loan is $9000.
D^2=x^2+y^2
d^2=(310+150cos20)^2+(150sin20)^2
d^2=205991.41373309
d=453.86mi
So C. to the nearest mile.
Answer:
y2 = C1xe^(4x)
Step-by-step explanation:
Given that y1 = e^(4x) is a solution to the differential equation
y'' - 8y' + 16y = 0
We want to find the second solution y2 of the equation using the method of reduction of order.
Let
y2 = uy1
Because y2 is a solution to the differential equation, it satisfies
y2'' - 8y2' + 16y2 = 0
y2 = ue^(4x)
y2' = u'e^(4x) + 4ue^(4x)
y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)
= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)
Using these,
y2'' - 8y2' + 16y2 =
[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0
u''e^(4x) = 0
Let w = u', then w' = u''
w'e^(4x) = 0
w' = 0
Integrating this, we have
w = C1
But w = u'
u' = C1
Integrating again, we have
u = C1x
But y2 = ue^(4x)
y2 = C1xe^(4x)
And this is the second solution