They could miss each other 30 different ways. I solved this by drawing it out six different stores and making Alice and Betsy go to each one may different times. Example photo included for how I got the first five. Then I did the same thing, but switch A and B, counted that towards the total and continued the is drawing until all the possibilities were found.
Answer:
The second option
Step-by-step explanation:
The given system of equation is
x+2y=3
-x+y+z=2
y-2z=-3
The augment matrix is obtained by combining the coefficient matrix with the constant matrix to obtain;
![\left[\begin{array}{cccc}1&2&0&|3\\-1&1&1&|2\\0&1&-2&|-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%260%26%7C3%5C%5C-1%261%261%26%7C2%5C%5C0%261%26-2%26%7C-3%5Cend%7Barray%7D%5Cright%5D)
Note that the absence of z, in the first equation means its coefficient is zero. The same thing applies to x in the last equation.
The correct choice is the second option.
If one is to choose among given choices and the order is not important, we use the concept of combination. First, we calculate for the sample space or number available since there is a total number of 12 electives and a student may choose 2 out of them.
S = 12C2
That is "the sample space is equal to combination of 12 taken 2". The answer to this is equal to 66.
Next, we determine the number of outcomes. The equation will be,
O = (5C1) x (3C1)
That is "outcome is equal to combination of 5 taken 1 times combination of 3 taken 1". This is equal to 15. The probability is equal to,
P = O/S
Substituting,
P = (15/66) = 0.227270
The answer to this item is the third choice.
Answer:
4.43
Step-by-step explanation:
7.90
- 3.47
__________
4. 4 3
I couldn't regroup but of you cross out 0 and put 10, 10-7= 3
and you have to borrow one from 9 and make it 8 and 8-4=4
