Weather conditions, temperature, and Food availability
Answer:
I would think it would be B Hope this helps out.
Explanation:
Answer:
(A) Sex-linked dominant
(B) Sex-linked recessive
Explanation:
This type of representation is used in pedigrees that express the inheritance of sex-linked characters, that is, those that are inherited through one of the sex chromosomes, which are the X or Y chromosomes.
For this reason it is necessary to represent males and females differently in the scheme
Answer: Plant vegetation so that their roots hold the soil firmly.
Build walls around the farm area.
Add natural fertilizers to the soil.
Soil erosion is a process of removal of top layer of soil which get sediment at some other place due to the affect of agents like wind and water. The superficial upper layers of soil are rich source of nutrients and organic matter and active region for germination of seeds and plant growth. Soil erosion removes these superficial layers making soil less fertile or not fertile and less useful for plant growth.
Plants growing in a vegetation have roots which can hold the soil and will prevent soil erosion from wind and water or any other agent. Building of walls around the farm area will prevent flood water to get inside the farm area and hence, prevents soil erosion by water. Addition of natural fertilizers to the soil adds up nutrients to the soil which facilitate plant growth and plant roots hold the soil therefore, prevents soil erosion.
Answer:
1. heterozygous yellow and star
2. 37
3. 1/8
4. 168
5. 1/4
Explanation:
Given ,
In f1 generation a cross is made between a true breeding black star bellied sneetch mated with a true breeding yellow starless sneetch
yySS x YYss
It is taken as - Y (yellow) is dominant over y (black)
and S (star) is dominant over s (starless)
1. F1 Generation
Genotype of parents yySS X YYss
gametes - yS, yS, Ys, Ys
All 16 offspring will have genotype YySs
phenotype would be heterozygous yellow and star
2. F2 generation cross
YySs X YySs
YS Ys yS ys
YS YYSS YYSs YySS YySy
Ys YYSs YYss YySs Yyss
yS YySS YySs yySS yySs
ys YySs Yyss yySs yyss
Genotype of offspring are –
YYSS – 1
YYSs – 2
YySS – 2
YySs – 4
YYss- 1
Yyss- 2
yySS – 1
yySs- 1
yyss- 1
2. Out of 16, 2 are black star bellied sneetches . Which means only 1/8 are black star bellied sneetches
So out of 300, 37 are black star bellied sneetches
3. Only 2 out of 16 are true breeding. i.e 1/8
4. 9 out of 16 are yellow star bellied sneetches, so out of 300, 168 are yellow star bellied sneetches
5. 4 out of 16 are true breeding yellow. Thus, ¼ are true breeding