Scenarios B, D, and F require a police officer. In scenario B, 1:00-2:00pm, and scenario F, 5:00-6:00pm, there are 24 cars. In scenario D, 3:00-4:00pm, there are 21 cars. Both 24 and 21 are greater than 17, so a traffic officer is needed. However, in other scenarios, the number of cars are all less than 17, and no officer is needed.
Answer:
-40 < t < 284
Step-by-step explanation:
The antifreeze protects the car between −40°C and 140°C.
Using t for temperature, the compound inequality of the Celsius temperature range is:
-40 < t < 140
The conversion formula is given to find degrees C in given degrees F. We can solve the formula for F, so we get degrees F in terms of degrees C.
C = (5/9)(F - 32) <------ <em>conversion formula from deg F to deg C</em>
Solve for F:
(9/5)C = F - 32
(9/5)C + 32 = F
F = (9/5)C + 32 <------ <em>conversion formula from deg C to deg F</em>
Now we convert -40 deg C to deg F using the formula we just derived.
F = (9/5)C + 32
F = (9/5)(-40) + 32
F = -72 + 32
F = -40
-40 deg C = -40 deg F
(This is not a mistake or a typo. -40 deg C really is the same as -40 deg F.)
Now we convert 140 deg C to deg F using the formula we just derived.
F = (9/5)C + 32
F = (9/5)(140) + 32
F = 252 + 32
F = 284
140 deg C = 284 deg F
Now we rewrite the compound inequality with Fahrenheit temperatures.
-40 < t < 284
Answer:
do you have a photo of the figure?
Answer:
StartFraction 1.55 over 1 EndFraction = StartFraction 3.5 over x EndFraction
Step-by-step explanation:
1 = 1.55
x = 3.5
1.55/1 =3.5/x
1.55/1 = 3.5/x correctly shows the equivalent ratios
Answer:
Step-by-step explanation:
So there is a 3% probability that an athlete is using EPO .
The probability of showing positive on a test when you've used it is 0.99.
3% x 0.99= 2.97%
The probability of a positive result without EPO is 0.1
97% x 0,1 = 9,7 %
My guess is that 2.97% + 9,7% = 12.67% or 0.1267.
I don't know i may be wrong because you've put as an answer 0.0297 but if you like you may take only the first part of the answer.