Let event A be the first light being red.
Let event B be the second light being red.
P(A) = 0.48
P(A & B) = P(A) * P(B) = 0.35
P(B) = 0.35 / P(A)
P(B) = 0.35 / 0.48
P(B) = 0.73
Since the lights are independent, P(B|A) = P(B) therefore d is the correct answer.
I would choose B. because first of all negative -2 can't be equal to -4 (but that's just my opinion)
Answer:
There are 16 yellow houses in the neighborhood.
Step-by-step explanation:
We have that:
2/5 = 40% of the houses are painted yellow
1 - 2/5 = 3/5 = 60% of the houses are not painted yellow
If there are 24 houses that are not painted yellow, how many yellow houses are in the neighborhood?
The first step is finding the total number of houses in the neighborhood.
We have that 24 are not painted yellow, and this is 60%(0.6 decimal). How much is 100%?
We solve a rule of three
24 houses - 0.6
x houses - 1



There are 40 houses. Of those, 40% are painted yellow.
0.4*40 = 16.
There are 16 yellow houses in the neighborhood.
Answer:

And we want to know what repreent the value 500 for this equation. If we see the general expression for an exponential function we have:

Where a is the constant or the initial amount, b te base and x the independnet variable (time)
For this special case we know that:

And 500 represent the constant or initial value for the function
Step-by-step explanation:
We have the following function given:

And we want to know what repreent the value 500 for this equation. If we see the general expression for an exponential function we have:

Where a is the constant or the initial amount, b te base and x the independnet variable (time)
For this special case we know that:

And 500 represent the constant or initial value for the function
Answer:
The fraction jumped into boiling water because it wanted to be reduced.
Step-by-step explanation:
This is a maths riddle about fractions. We often see fractions that we might feel could be reduced. So, if these kinds of fractions jumps into a boiling water, they get reduced. The riddle is rather funny though.