Question

a line passing through the point (12, - 5) has a slope of 1/3. Complete the work shown. Substitute known values for m, x1, and y1. Distribute the slope through the parentheses, solve for the y variable

Answer 1

Answer:

the answer is -9

Step-by-step explanation:

i took the test and got it right

Answer 2

The solution for the variable y is $y=\frac{1}{3} x-9$, if a given line passing through the point (12, -5) has a slope of $\frac{1}{3}$.

Step-by-step explanation:

The given is,

                         Point - (12, -5)

                         Slope - $\frac{1}{3}$

Step:1

          Formula for slope of line,

                                     $m = \frac{y_{2}-y_{1} } {x_{2} - x_{1} }$...........................(1)

         Where, $(x_{1} ,y_{1} )$, $(x_{2} ,y_{2} )$ are points

                      m - Slope

         From given,

                     (12, -5) -  $(x_{1} ,y_{1} )$

                      m = $\frac{1}{3}$

         Let, (x,y ) = $(x_{2} ,y_{2} )$

         Equation (1) becomes,

                                  $\frac{1}{3} = \frac{(y - (-5))}{x-12}$

                     $\frac{1}{3} (x-12) = (y-(-5))$

                     $\frac{1}{3} (x-12) = (y+5)$

                         $(y+5) = \frac{1}{3} (x-12)$

                         $(y+5) = (\frac{1}{3} x ) -\frac{1}{3}(12))$

                          $(y+5) = (\frac{1}{3} x ) -4$

                                   $y = \frac{1}{3} x -4-5$

                                   $y = \frac{1}{3} x -9$

Result:

       The solution for the variable y is $y=\frac{1}{3} x-9$, if a given line passing through the point (12, -5) has a slope of $\frac{1}{3}$.