Answer:
Option d)
Step-by-step explanation:
We are given the following in the question:
Three of four people believed that the state of the economy was the country's most significant concern.
They would like to test the new data against this prior belief.
The null hypothesis will state that the three of four people believed that the state of the economy was the country's most significant concern.
The alternate hypothesis will state that this is not true. It states that people believed that the state of the economy was the country's most significant concern is not the same.
We design the null and the alternate hypothesis
Let the width of the yard be w.
Since the length is 18feet longer, l = w + 18
Perimeter for rectangle = 2(l + w)
2(l + w) = 72
2(w+18 + w) = 72 Divide 2 on both sides
(w + 18 + w) = 36
2w + 18 = 36
2w = 36 - 18
2w = 18 Divide 2 on both sides
w = 18/2
w = 9
Recall, length l = w + 18, l = 9 + 18 = 27
Hence width, w = 9, length,l = 27
Area of rectangle = l × w = 27 × 9 = 243
Area of rectangular yard = 243 square feet.
Answer:
Geometric
Step-by-step explanation:
A geometric setting does not have a set number of trials, and the variable in question is the number of trials it takes to get the first success.
The upgrades are independent, and the probability of the customer upgrading is the same each time.
Answer: a) 0.25, b) 0.78, c) 0.71
Step-by-step explanation:
Since we have given that
Number of employees in marketing = 4
Number of employees in management = 7
We need to hire committee of 3 people.
a) Find the probability that the committee has exactly 2 employees from marketing.
So, Probability becomes
b) Find the probability that the committee has at least one employee from marketing.
c) Find the probability that the committee has at most one employee from management.
Hence, a) 0.25, b) 0.78, c) 0.71
Answer:
P(A) = 0.2
P(B) = 0.25
P(A&B) = 0.05
P(A|B) = 0.2
P(A|B) = P(A) = 0.2
Step-by-step explanation:
P(A) is the probability that the selected student plays soccer.
Then:
P(B) is the probability that the selected student plays basketball.
Then:
P(A and B) is the probability that the selected student plays soccer and basketball:
P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:
P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.
