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vichka [17]
2 years ago
13

Andrew recently started hanging out with a group of peers who are all motivated to do well in school and are involved in academi

c extracurricular activities, such as the debate team and the science fair. Andrew's gravitation to this group of peers is known as:
A. selection.
B. peer pressure.
C. facilitation.
D. deviancy training.
Social Studies
2 answers:
Elodia [21]2 years ago
5 0

Answer:

A. Selective.

Explanation:

This could be looked at in the sense of a little disorder from little Andrew, though the act is selective, it could also come up as mutuism. Some adults with selective mutism are fully capable of speech and understanding language but are physically unable to speak in certain situations, though speech is expected of them.

The behaviour may be perceived as shyness or rudeness by others. A child with selective mutism may be completely silent at school for years but speak quite freely or even excessively at home. There is a hierarchical variation among people with this disorder: some people participate fully in activities and appear social but do not speak, others will speak only to peers but not to adults, others will speak to adults when asked questions requiring short answers but never to peers, and still others speak to no one and participate in few, if any, activities presented to them.

kaheart [24]2 years ago
4 0

Answer:

A. selection

Explanation:

Selection is a process whereby an individual in a society become associated with a group of individuals or people based on a preference or attribute they consider pleasant in them or they share the same attributes, and as such, interact with such group of individuals. This interaction often yields some degree of cooperation or helpfulness.

According to the information given about Andrew in the question, we can infer that Andrew's gravitation to this group of peers is known as selection.

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A farmer divided his piece of land into 4 equivalent groups. The quality of the soil is the same across the 4 groups of land. He
almond37 [142]

Answer: Experimental

Explanation:

Experimental study is the study in which researcher has some control over the variables where he can experiment and test over the groups. Observational study provides no control to researcher .He can only observe the process.

According to the question, study conducted by farmer is experimental as farmer has the control over quantity variable of land , grouping choice of crop etc.He is dividing  the land equally in four parts,sowing same crops into 4 groups in each piece depicts that he is testing or experimenting everything equally.

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2 years ago
A section of highway is posted with a 55 mph speed limit. In fact, speeds of cars traveling on this section are normally distrib
In-s [12.5K]

Answer:

z=1.28

And if we solve for a we got

a=58 +1.28*5=64.4

So the value of height that separates the bottom 90% of data from the top 10% is 64.4.  

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the velocity of a population, and for this case we know the distribution for X is given by:

X \sim N(58,5)  

Where \mu=58 and \sigma=5

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.10   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.90 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=58 +1.28*5=64.4

So the value of height that separates the bottom 90% of data from the top 10% is 64.4.  

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