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Aleks [24]
2 years ago
3

please help!!!!!!!!! Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Baseline) (y

Superscript negative 2 Baseline) Over 2 (x Superscript 4 Baseline) (y superscript negative 4 Baseline) EndFraction) Superscript negative 3, when x = negative 1 and y = 2. Step 1: Substitute x = negative 1 and y = 2 into the expression. (StartFraction (negative 1) Superscript negative 3 Baseline (2) Superscript negative 2 Baseline Over 2 (negative 1) Superscript 4 Baseline (2) superscript negative 4 Baseline) EndFraction) Superscript negative 3 Step 2: Simplify the parentheses. (StartFraction (2) Superscript 4 Baseline Over 2 (negative 1) Superscript 4 Baseline (negative 1) cubed (2) squared EndFraction) Superscript negative 3 Baseline = (StartFraction (2) squared Over 2 (negative 1) Superscript 7 Baseline EndFraction) Superscript negative 3 Step 3: Evaluate the power to a power. StartFraction (2) Superscript negative 6 Baseline Over 2 Superscript negative 3 Baseline (negative 1) Superscript negative 21 baseline EndFraction Step 4: Use reciprocals and find the value. StartFraction 1 Over 2 cubed (2) Superscript 6 Baseline (negative 1) Superscript 21 Baseline EndFraction = StartFraction 1 Over 8 times 64 times (negative 1) EndFraction = Negative StartFraction 1 Over 512 EndFraction In which step did Rena make the first error? Step 1 Step 2 Step 3 Step 4
Mathematics
2 answers:
ElenaW [278]2 years ago
8 0

Answer:

c

Step-by-step explanation:

its just c

cluponka [151]2 years ago
6 0

Answer:

the correct answer is c

Step-by-step explanation:

i got it right on my unit test

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