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Daniel [21]
2 years ago
15

The distribution of the amount of money spent by students for textbooks in a semester is approximately normal in shape with a me

an of $235 and a standard deviation of $20. According to the standard deviation rule, almost 2.5% of the students spent more than what amount of money on textbooks in a semester?
Mathematics
1 answer:
faust18 [17]2 years ago
4 0

Answer:

Almost 2.5% of the students spent more than $275 in a semester.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 235

Standard deviation = 20

According to the standard deviation rule, almost 2.5% of the students spent more than what amount of money on textbooks in a semester?

95% of the measures are within 2 standard deviation of the mean. The other 5% are more than 2 standard deviations of the mean. Since the normal distribution is symmetric, 2.5% of those are below two standard deviations of the mean and 2.5% are more than two standard deviations above the mean.

235 + 2*20 = $275

Almost 2.5% of the students spent more than $275 in a semester.

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The product of three integers is −5. Determine all of the possible values for the three factors.
tensa zangetsu [6.8K]
-1,1,5
-1,-1,-5
1,1,-5
6 0
2 years ago
A series contains 18 numbers and has a sum of 4,185. The last number of the series is 275. What is the first number?
dusya [7]
The sum of arithmetic series is given by:
Sn=n/2(a1+an)
where:
n=number of terms
a1=first term
an=nth term
but
n=18, an=275, Sn=4185
plugging the values in the formula we get:
4185=18/2(a1+275)
simplifying this we get:
4185=9(a1+275)
dividing through by 9 we get:
465=a1+275
thus
a1=465-275
a1=190

Answer: first number is 190
3 0
2 years ago
How much money do winners go home with from the television quiz show Jeopardy? To determine an answer, a random sample of winner
Liula [17]

Answer:

The 95% confidence interval would be given by (14444.04;33657.30)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data: $26,650 $6,060 $52,820 $8,490 $13,660$25,840 $49,840 $23,790 $51,480 $18,960$990 $11,450 $41,810 $21,060 $7,860

We can calculate the mean and the deviation from these data with the following formulas:

\bar X= \frac{\sum_{i=1}^n x_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}

\bar X=24050.67 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=17386.13 represent the sample standard deviation

n=15 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=15-1=14

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,14)".And we see that t_{\alpha/2}=2.14

Now we have everything in order to replace into formula (1):

24050.67-2.14\frac{17386.13}{\sqrt{15}}=14444.04    

24050.67+2.14\frac{17386.13}{\sqrt{15}}=33657.30

So on this case the 95% confidence interval would be given by (14444.04;33657.30)    

6 0
1 year ago
Lucia is making a 21.6 centimeter beaded string to hang in the window. She decides to put a green bead every 0.4 centimeters and
olasank [31]
21.6 ÷ 0.4 = 54 times for green
21.6 ÷ 0.6 = 36 times for purple

Together, 90 beads. Separately, 54 green and 36 purple.
3 0
1 year ago
Read 2 more answers
The distribution of waist circumferences of US adult men randomly selected for a research study was approximately normal with me
kow [346]

Answer: 99cm

Step-by-step explanation:

5 0
1 year ago
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