answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Daniel [21]
2 years ago
15

The distribution of the amount of money spent by students for textbooks in a semester is approximately normal in shape with a me

an of $235 and a standard deviation of $20. According to the standard deviation rule, almost 2.5% of the students spent more than what amount of money on textbooks in a semester?
Mathematics
1 answer:
faust18 [17]2 years ago
4 0

Answer:

Almost 2.5% of the students spent more than $275 in a semester.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 235

Standard deviation = 20

According to the standard deviation rule, almost 2.5% of the students spent more than what amount of money on textbooks in a semester?

95% of the measures are within 2 standard deviation of the mean. The other 5% are more than 2 standard deviations of the mean. Since the normal distribution is symmetric, 2.5% of those are below two standard deviations of the mean and 2.5% are more than two standard deviations above the mean.

235 + 2*20 = $275

Almost 2.5% of the students spent more than $275 in a semester.

You might be interested in
Leo needs 10 red roses and 15 pink daisies for every 5 bouquets he makes for a flower shop. Drag red roses and pink daisies into
Lelechka [254]
For this equation, you need only 2 red roses and 3 pink daisies to make 1 boutique. 
So, just multiply 3 * 2 and 3 * 3. 
Which is 6 and 9, then add the two together = 15.
Hope this helps!!
8 0
2 years ago
Read 2 more answers
A sign language club made $627.50 from selling popcorn at a festival. The popcorn cost the club $95.00. Which expression represe
Vlad1618 [11]
C because you have to divide by m or the members because you are splitting it up or dividing it between the members. And you subtract 95 dollars becuase it was a cost or bill
7 0
2 years ago
Read 2 more answers
Suppose that you want to mix two coffees in order to obtain 100 pounds of a blend. If x represents the number of pounds of coffe
Svetach [21]

Answer: 100-x

Therefore, the algebraic exp

Step-by-step explanation:

Given : x represents the number of pounds of coffee​ A.

The total weight of the mix of coffee A and coffee B = 100 pounds.

Then , we have the following expression to represents the number of pounds of coffee B:-

100-x

Therefore, the algebraic expression that represents the number of pounds of coffee B. :-

100-x

5 0
2 years ago
A craft vendor must sell at least $300 worth of merchandise to make a profit. Scarves sell for $10 each and hats sell for $20 ea
valina [46]
There is a missing graph in the problem given. However, we can simply solve the equation using the given data.

Items to be sold: scarves and hats. Minimum of 20 items sold in all.
Scarves sell for 10 each and hats sell for 20 each. Must sell at least 300 worth of merchandise to make profit. 

Let s represent scarves and h represent hats.

10s + 20h <u>></u> 300
s + h <u>></u> 20

We use inequality because the problem states "at least". 

s + h = 20
10s + 20h = 300

s = 20 - h
10(20-h) + 20h = 300
200 - 10h + 20h = 300
10h = 300 - 200
10h = 100
h = 100/10
h = 10

s = 20 - h
s = 20 - 10
s = 10

s + h <u>></u> 20
10 + 10 <u>></u> 20

10s + 20h <u>></u> 300
10(10) + 20(10) <u>></u> 300
100 + 200 <u>></u> 300

7 0
2 years ago
Read 2 more answers
What are the factors of the polynomial function? Use the rational root theorem to determine the factors. f(x) = 2x³ + x² - 8x -
fredd [130]

Answer:

( x + 2 ) ( x - 2 ) ( 2x + 1)

Step-by-step explanation:

coefficient of x³ is 2 and denote it with q and denote -4 as p

the set of possible rational roots through rational theorem will be within ± (p/q)

now factors of -4 are ±(1,2,4) and factors of 2 are ± (1,2) the possible rational roots are ± ( 1/1, 1/2, 2/1, 2/2, 4/1, 4/2) which reduces to ± (1, 1/2, 2, 4)

substitute each of the value into the equation

f(x) = 2x³ + x² - 8x - 4 to the root ( that gives f(x) = 0)

the equation can be made easy writing it in reduced form

2x³ + x² - 8x - 4

(2x³ + x²) - (8x + 4)

x² (2x + 1) - 4 (2x + 1)

(x² - 4) (2x + 1)

( x + 2 ) ( x - 2) ( 2x + 1) are the factors which correspond to 2, -2, -1/2 roots

4 0
2 years ago
Other questions:
  • marta bought new fish for her home aquarium. she bought 3 guppies and 2 platies for a total of 13.95. hank also ought guppies an
    7·1 answer
  • a printing press will print 6,000 copies in 20 minutes. A second press can print 15000 copies in 60 minutes. How many more copy
    8·1 answer
  • According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 9x^4 – 2x^2 – 3x + 4?
    11·2 answers
  • A statistics professor receives an average of five e-mail messages per day from students. assume the number of messages approxim
    15·2 answers
  • Is the graph increasing, decreasing, or constant?
    15·2 answers
  • Write the phase "3 times the difference of 5 and y equals 4" as a variable expression:
    10·2 answers
  • Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the
    7·1 answer
  • On each trial of a digit span memory task, the participant is asked to read aloud a string of random digits. The participant mus
    8·1 answer
  • Lines j and k are intersected by line m. At the intersection of lines j and m, the uppercase left angle is 93 degrees. At the in
    11·2 answers
  • Determine the area of squre ABCD with AB=3cm<br>​
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!