To rebuild and repair the muscles in the body when it get damaged.
Answer:
The homozygous dominant phenotype is higher than expected, indicating that evolution has occurred.
Explanation:
At the start there are 200 fishes in the pond, 100 of them are AA(50%) and 100 of them are aa(50%). Using the Hardy-Weinberg Equilibrium equation we can say that the gene frequency is
A=0.5
a=0.5
With those frequency, the expected percentage of offspring with dominant genotype will be:
AA= 0.5 * 0.5 = 0.25 = 25%
The number of homozygous dominant found is 35% which is higher than expected (25%). Higher homozygous dominant frequency than expected means the Hardy-Weinberg Equilibrium is changed. In this case, evolution probably the cause that shifts the gene frequency.
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
The answer your looking for is c hope it helps
and #rateme
