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2 years ago

7

Mrs. Ibarra wants to create a right triangle for a geometry test. She plans to use 15, 36, and 41 as side lengths. Which stateme

nts should she consider to determine whether it will be a right triangle? Check all that apply.

2 answers:

Arisa [49]2 years ago

6 0

Answer:

Step-by-step explanation:

The answer is A, C, D, and E. I just took the test.

scoray [572]2 years ago

6 0

The answer is A, C, D, and E.

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An athlete jumped 5.5 feet which was 1.1 times higher than the previous jumper how high did the previous athlete jump

Fantom [35]

Answer:

5 ft

Step-by-step explanation:

Let the height of the previous jump be represented by j. Then 1.1j = 5.5 ft.

Dividing both sides by 1.1, we get j = 5 ft. This was the height of the previous jump.

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2 years ago

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Zack wants to make a profit of more than $300 for painting 4 identical rooms. The profit he makes is equal to the amount he is p

lianna [129]

Answer: A

n-4(32.5) > 300;n > 430tep-by-step explanation:

given that Zack wants to make a profit of more than $300 for painting 4 identical rooms. That is

Profit > $300

Then, the profit he makes is equal to the amount he is paid minus the cost of supplies. The cost of supplies is $32.50 for each room. That is

n - 32.5 and

P + 32.5 × 4

Where 4 = number of rooms

P + 130

The minimum profit = 300 + 130 = $430

Therefore, the inequality and solution that represent the dollar amount, n, that zack must be paid for each room if he is to make a profit of more than 300$ is

n-4(32.5) > 300;n > 430

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2 years ago

Read 2 more answers

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

Mrac [35]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have $DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute $A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

2 years ago

Hiromi sells 12 T-shirts each week at a price of $13.00. Past sales have shown that for every $0.25 decrease in price, 4 more T-

Lerok [7]

(13-0.25x4)(12+4x4)=2,464
(13-0.25x5)(12+4x5)=3,845
(13-0.25x6)(12+4x6)=2,845
so your answer is 3,845 because if Hirome sells them for $11.75 he makes $3845 if Hirome sold them for $11.50 he makes $2845.80 and if he sold them for $12.00 he would make $2464.00

4 0

2 years ago

A supervisor records the repair cost for 17 randomly selected stereos. A sample mean of $66.34 and standard deviation of $15.22

expeople1 [14]

Answer:

Critical value: T = 1.337

The 80% confidence interval for the mean repair cost for the stereos is between $45.991 and $86.689

Step-by-step explanation:

We have the standard deviation for the sample. So we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 17 - 1 = 16

80% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 16 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.8}{2} = 0.9$ . So we have T = 1.337, which is the critical value

The margin of error is:

M = T*s = 1.337*15.22 = 20.349

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 66.34 - 20.349 = $45.991

The upper end of the interval is the sample mean added to M. So it is 66.34 + 20.349 = $86.689

The 80% confidence interval for the mean repair cost for the stereos is between $45.991 and $86.689

3 0

2 years ago