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Sholpan [36]
2 years ago
7

Mrs. Ibarra wants to create a right triangle for a geometry test. She plans to use 15, 36, and 41 as side lengths. Which stateme

nts should she consider to determine whether it will be a right triangle? Check all that apply.

Mathematics
2 answers:
Arisa [49]2 years ago
6 0

Answer:

Step-by-step explanation:

The answer is A, C, D, and E. I just took the test.

scoray [572]2 years ago
6 0

The answer is A, C, D, and E.

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It going to be 79 mile 
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A company logo is made up of a square and three identical triangles. What is the area of the logo? Enter your answer in the box.
garri49 [273]
Given:
square with sides measuring 7 cm.
3 triangles attached to three sides of the square. A line bisecting one triangle is measured at 4 cm.

Area of a square = s² = (7cm)² = 49 cm²

Area of a triangle = hb/2 = (4cm*7cm)/2 = 14 cm² 
Area of the 3 triangles = 14 cm² x 3 = 42 cm²

Total area of the logo = 49 cm² + 42 cm² = 91 cm²
7 0
2 years ago
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Megan wants to build a fence around her pool. The pool is 28 feet long by 23 feet wide. The fence is to be 15 feet from the edge
ASHA 777 [7]
23 +30 (15 feet each way) = 53

28 + 30 = 58

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2 years ago
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A
gavmur [86]

Answer:

m∠QPM=43°

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m∠NPQ=m∠MPN+m∠MPQ

we have

m∠NPQ=(9x-25)°

m∠MPN=(4x+12)°

m∠MPQ=(3x-5)°

substitute the given values and solve for x

(9x-25)°=(4x+12)°+(3x-5)°

(9x-25)°=(7x+7)°

9x-7x=25+7

2x=32

x=16

Find the measure of angle QPM

Remember that

m∠QPM=m∠MPQ

m∠MPQ=(3x-5)°

substitute the value of x

m∠MPQ=(3(16)-5)=43°

therefore

m∠QPM=43°

7 0
2 years ago
Circle A and circle B are congruent. CD is a chord of both circles. If AB = 8 ft and CD = 6 ft, how long is a radius?
bazaltina [42]

Let us say that the intersection point of lines AB and CD is called point E. The lines AB and CD are perpendicular to each other which also means that the triangle CEB is a right triangle.

Where the line CB is the radius of the circle while the side lengths are half of the whole line segment:

EB = 0.5 AB = 0.5 (8 ft) = 4 ft

CE = 0.5 CD = 0.5 (6 ft) = 3 ft

Now using the hypotenuse formula since the triangle is right triangle, we can find for the radius or line CB:

CB^2 = EB^2 + CE^2

CB^2 = (4 ft)^2 + (3 ft)^2

CB^2 = 16 ft^2 + 9 ft^2

CB^2 = 25 ft^2

<span>CB = 5 ft = radius</span>

7 0
2 years ago
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