Answer:
Step-by-step explanation:
1 ) Given that
For a non homogeneous part 
, we assume the particular solution is
2 ) Given that
For a non homogeneous part 
, we assume the particular solution is
3 ) Given that
y′′ + 4y′ + 20y = −3sin(2x)
For a non homogeneous part −3sin(2x) , we assume the particular solution is
4 ) Given that
y′′ − 2y′ − 15y = 3xcos(2x)
For a non homogeneous part 3xcos(2x) , we assume the particular solution is
Answer:
I'm sorry all I know is part a is 40
Step-by-step explanation:
hope this helps you answer all of the other parts.
=) =) =U
It is definitely D because on part 1 n=24n+20 and if n equals 0 than 24 (0) +20= 20 and that is true. on part 2 if n =0 than 24 (0)+ 20 (0-1)=20 than 20 (-1)=20 -20= 20. that statement is false because-20 does not equal 20. AND for part 3 n=1 and f (1-1) + 24= 44 so f (0) + 24 =44 and keep in mind f (0) equals 20 so 44=44 because 24+20 is 44. so that is a true statement too
Answer:
a. The sample has more than 30 grade-point averages.
Step-by-step explanation:
Given that a researcher collects a simple random sample of grade-point averages of statistics students, and she calculates the mean of this sample
We are asked to find the conditions under which that sample mean can be treated as a value from a population having a normal distribution
Recall central limit theorem here
The central limit theorem states that the mean of all sample means will follow a normal distribution irrespective of the original distribution to which the data belonged to provided that
i) the samples are drawn at random
ii) The sample size should be atleast 30
Hence here we find that the correct conditions is a.
Only option a is right
a. The sample has more than 30 grade-point averages.
Answer: option D is the correct answer
Step-by-step explanation:
The shaded portion of the circle is the smaller sector whose radius is the same as the radius of the circle which is given as 4 units. The sector is always bounded by two radii with a common point which is the center of the circle and forming an angle at that point. The given sector forms an angle of 45 degrees.
Area of a sector is expressed as
#/360 × π × r^2 and # is in degrees
Therefore, area of the shaded portion or sector = 45/360 × π × 4^2
= 45/360 × 16π
= 45/360 (16π)
