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Annette [7]
2 years ago
14

The owner of a sandwich shop researches the cost of buying different numbers of pounds of sandwich meat. The owner creates a sca

tter plot of the data.
The owner then draws two different functions to model the data and plots the residuals for each function, as shown below.



Select each statement that is true regarding these two functions.
Mathematics
1 answer:
IgorC [24]2 years ago
3 0

Answer:

what r the statementzsssssssssssssssssssssssssssssssssss

Step-by-step explanation:

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Answer: 18060

<u>Step 1</u>

1806(8−3)(2)

<u>Step 2</u>

(1806)(5)(2)

<u>Step 3</u>

(9030)(2)

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Luis made 80% of what he made last week.If he made 72$ this week,how much did he make last week
IceJOKER [234]

Let

x--------> the amount in dollars that Luis make last week

we know that

80\% =\frac{80}{100}=0.80

0.80x=72\$ ------> equation that represent the situation

solve for x

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0.80x/0.80=72\$/0.80

x=72\$/0.80

x=90\$

therefore

<u>the answer is</u>

90\$

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Z varies directly as x squaredx2. If zequals=50 when xequals=5,find z when
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5=x dived by z

Step-by-step explanation:

3 0
2 years ago
A taut string of length 10 inches is plucked at the center. The vibration travels along the string at a constant rate of c inche
Mademuasel [1]

Answer:

The correct option is

A.  \ \dfrac{1}{c} \times \left | x - 5 \right | = 0.3

Step-by-step explanation:

The parameters given are;

The length of the string = 10 inches

The speed or rate of travel of the wave = c inches per millisecond

The position on the string from the left-most end = x

The time duration of motion of the vibration to reach x= 0.3 milliseconds

The distance covered = Speed × Time = c×0.3

Given that the string is plucked at the middle, with the vibration travelling in both directions, the point after 0.3 millisecond is x where we have;

The location on the string where it is plucked = center of the string = 10/2 = 5 inches

Distance from point of the string being plucked (the center of the string) to the left-most end = 5 inches

Therefore, on the left side of the center of the string we have;

The distance from the location of the vibration x (measured from the left most end) to the center of the string = 5 - x = -(x -5)

On the right side of the center, the distance from x is -(5 - x) = x - 5

Therefore, the the equation that can be used to find the location of the vibration after 0.3 milliseconds is \dfrac{1}{c} \times \left | x - 5 \right | = 0.3 or \left | x - 5 \right | = 0.3 \times c which gives the correct option as A

8 0
2 years ago
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